Problem 66
Question
Simplify each expression. Rationalize all denominators. Assume that all variables are positive. $$ \frac{\sqrt{62}}{\sqrt{6}} $$
Step-by-Step Solution
Verified Answer
The simplified form of the expression \( \sqrt[6]{\frac{y^{-3}}{x^{-4}}} \) is \( x^{\frac{2}{3}} \cdot \frac{1}{y^{\frac{1}{2}}} \)
1Step 1: Convert the Root to an Exponent
The expression given is \( \sqrt[6]{\frac{y^{-3}}{x^{-4}}} \). The square root of \( \frac{y^{-3}}{x^{-4}} \) to the power of 6 is equal to \( (\frac{y^{-3}}{x^{-4}}) ^ {\frac{1}{6}} \).
2Step 2: Simplify the Exponential Expression
Using exponent rules, simplify the expression to give \( (\frac{1/y^3}{1/x^4})^{\frac{1}{6}} \) which equates to \( (\frac{x^4}{y^3})^{\frac{1}{6}} \).
3Step 3: Distribute the Exponent
Next, apply the exponent \( \frac{1}{6} \) to both \( x^4 \) and \( y^3 \) based on the rule \( (a\cdot b)^n = a^n \cdot b^n \) to get the simplified form \( x^{\frac{4}{6}} \cdot y^{-\frac{3}{6}} \)
4Step 4: Simplify the Fractional Exponents
Fractional exponent \( x^{\frac{4}{6}} \) simplifies to \( x^{\frac{2}{3}} \), and \( y^{-\frac{3}{6}} \) simplifies to \( y^{-\frac{1}{2}} \)
5Step 5: Rationalize the Denominator
Rationalizing the denominator means rewriting the expression so that there are no roots (or fractional powers) of numbers and variables in the denominator. Since \( a^{-n} = \frac{1}{a^n} \), \( y^{-\frac{1}{2}} \) can be rewritten as \( \frac{1}{y^{\frac{1}{2}}} \), this gives the final simplified form of the expression as \( x^{\frac{2}{3}} \cdot \frac{1}{y^{\frac{1}{2}}} \)
Key Concepts
Simplifying Exponential ExpressionsFractional ExponentsRoot to Exponent Conversion
Simplifying Exponential Expressions
Exponential expressions can sometimes look complicated, but by understanding the basic rules, you can simplify them easily. Let's break it down with a focus on the expression\[\left(\frac{x^4}{y^3}\right)^{\frac{1}{6}}\]. First, remember that when you have a fraction raised to an exponent, you need to distribute the exponent to both the numerator and the denominator.
- This means applying the exponent \(\frac{1}{6}\) to both \(x^4\) and \(y^3\).
- As a result, you get \(x^{\frac{4}{6}}\) and \(y^{\frac{3}{6}}\).
Fractional Exponents
A fractional exponent is another way to represent roots, and simplifying them often involves converting the root to an exponent. In our exercise, after converting the root operation to fractional exponents, the expression becomes\[x^{\frac{4}{6}} \cdot y^{\frac{-3}{6}}\].The numerator of the fraction represents the power, while the denominator represents the root:
- For example, \(x^{\frac{4}{6}}\) can be interpreted as \(\sqrt[6]{x^4}\).
- Similarly, \(y^{\frac{-3}{6}}\) indicates a sixth root raised to a power of \(-3\).
Root to Exponent Conversion
Converting roots to exponents is a powerful technique in algebra that helps simplify complex expressions. When faced with an expression like\[\sqrt[6]{\frac{y^{-3}}{x^{-4}}}\],realize that you can transform it to an exponential form for easier manipulation:
- In general, \(\sqrt[n]{a} = a^{\frac{1}{n}}\).
- Therefore, the sixth root of \(\frac{y^{-3}}{x^{-4}}\) becomes \((\frac{y^{-3}}{x^{-4}})^{\frac{1}{6}}\).
Other exercises in this chapter
Problem 66
Simplify each expression. \(25^{1.5}\)
View solution Problem 66
For each pair of functions, find \(f(g(x))\) and \(g(f(x))\) $$ f(x)=\frac{x-3}{2}, g(x)=2 x-3 $$
View solution Problem 66
Simplify each radical expression. \(n\) is an odd number. $$ \sqrt[n]{m^{n}} $$
View solution Problem 66
Simplify each expression. Assume that all variables are positive. $$y^{\frac{1}{2}} \cdot y^{\frac{3}{10}}$$
View solution