Problem 66
Question
Let's look more closely at the process of hybridization. (a) What is the relationship between the number of hybrid orbitals produced and the number of atomic orbitals used to create them? (b) Do hybrid atomic orbitals form between different \(p\) orbitals without involving \(s\) orbitals? (c) What is the relationship between the energy of hybrid atomic orbitals and the atomic orbitals from which they are formed?
Step-by-Step Solution
Verified Answer
(a) The number of hybrid orbitals equals the number of atomic orbitals used. (b) No, they usually require 's' orbitals. (c) Hybrid orbitals' energy is intermediate between the original orbitals' energies.
1Step 1: Understanding Hybrid Orbital Formation
Hybrid orbitals are formed when atomic orbitals within the same atom mix. The number of hybrid orbitals produced is equal to the number of atomic orbitals mixed. For example, when one 's' orbital mixes with three 'p' orbitals, they form four sp³ hybrid orbitals.
2Step 2: Mixing of Orbitals
Hybrid orbitals usually involve the mixing of different types of atomic orbitals, such as 's' and 'p'. It is uncommon for hybridization to involve only 'p' orbitals without 's' orbitals because the 's' orbital provides spherical symmetry and increases the overlap efficiency with 'p' orbitals.
3Step 3: Energy Considerations in Hybrid Orbitals
The energy of the resulting hybrid orbitals is intermediate between the energies of the atomic orbitals from which they were derived. For instance, if 's' and 'p' orbitals hybridize, the energy of the new hybrid orbitals will be between the energy levels of the original 's' and 'p' orbitals.
Key Concepts
Understanding Atomic OrbitalsThe Formation of Hybrid OrbitalsEnergy Levels and Hybrid Orbital Formation
Understanding Atomic Orbitals
Atomic orbitals are regions in an atom where electrons are most likely to be found. Each orbital represents a solution to the Schrödinger equation for electrons in an atom. They possess distinct shapes, sizes, and energy levels. Common types of atomic orbitals include:
- s orbitals: These are spherical and can be found at all energy levels.
- p orbitals: Characterized by their dumbbell shape, p orbitals are available from the second energy level (n=2) upwards.
- d and f orbitals: These orbitals have more complex shapes and are found only at higher energy levels (n=3 for d orbitals and n=4 for f orbitals).
The Formation of Hybrid Orbitals
Hybrid orbitals result from the mixing of two or more atomic orbitals from the same atom. The primary purpose of forming hybrid orbitals is to facilitate the bonding between atoms, improving symmetry and orbital overlap. The concept can be broken down as follows:
- Equality in Number: The number of hybrid orbitals formed is always equal to the number of atomic orbitals mixed. For example, if one s and two p orbitals mix, the outcome is three identical sp² hybrid orbitals.
- Inclusion of Different Types: Typically, hybridization involves mixing different types of atomic orbitals, like s and p orbitals, to create new orbitals with shapes that are optimal for bonding.
Energy Levels and Hybrid Orbital Formation
Hybrid orbitals exhibit energy levels that are intermediate relative to their constituent atomic orbitals. The concept of energy levels in this context is key to understanding why hybrid orbitals form:
- Intermediate Energy: When atomic orbitals hybridize, the resultant hybrid orbitals have energy levels that lie between the energies of the original orbitals. For example, in an sp³ hybridization involving one s and three p orbitals, the energy of the sp³ orbitals falls between that of the s and p orbitals.
- Stability via Hybridization: Hybridization tends to lower the energy gap and creates more stable bonding environments by facilitating effective orbital overlap.
Other exercises in this chapter
Problem 62
What is the connection between bond order, bond length, and bond energy? Use ethane \(\left(\mathrm{C}_{2} \mathrm{H}_{6}\right)\), ethylene \(\left(\mathrm{C}_
View solution Problem 64
Show how valence bond theory and molecular orbital theory rationalize the O-O bond order of 1.5 in ozone.
View solution Problem 70
Melamine is an important industrial chemical, used to make fertilizers and plastics. (a) The carbon-nitrogen bond lengths in the ring are all the same length (a
View solution Problem 71
Bromine forms a number of oxides of varying stability. (a) One oxide has \(90.90 \%\) Br and \(9.10 \%\) O. Assuming its empirical and molecular formulas are th
View solution