Problem 66
Question
\(\left({ }^{\mathrm{m}} C_{0}+{ }^{\mathrm{m}} C_{1}-{ }^{\mathrm{m}} C_{2}-{ }^{\mathrm{m}} C_{3}\right)+\left({ }^{\mathrm{m}} C_{4}+{ }^{\mathrm{m}} C_{5}-{ }^{\mathrm{m}} C_{6}-{ }^{\text {" }} C_{7}\right)+\ldots\) \(=0\) if and only if for some positive integer \(k, m=\) (A) \(4 k\) (B) \(4 k+1\) (C) \(4 k-1\) (D) \(4 k+2\)
Step-by-Step Solution
Verified Answer
The correct answer is (C) \(4k-1\).
1Step 1: Understanding the Expression
The given expression is a series of combinations, or binomial coefficients, which are symmetric in nature. The terms are split into groups of four with alternating signs: \( \left({ }^{\mathrm{m}} C_{0}+{ }^{\mathrm{m}} C_{1}-{ }^{\mathrm{m}} C_{2}-{ }^{\mathrm{m}} C_{3}\right) \), and this pattern continues for subsequent terms.
2Step 2: Analyze the Group Patterns
Each group has the structure: \( { }^{\mathrm{m}} C_{4k} + { }^{\mathrm{m}} C_{4k+1} - { }^{\mathrm{m}} C_{4k+2} - { }^{\mathrm{m}} C_{4k+3} \). Writing the next group, using patterns, is similar but offset by 4.
3Step 3: Sum of Each Group
To find the sum of each group, notice that the binomial coefficients have a property that every group sums to zero for certain values of \(m\). Expanding one group:\( { }^{\mathrm{m}} C_{0} + { }^{\mathrm{m}} C_{1} - { }^{\mathrm{m}} C_{2} - { }^{\mathrm{m}} C_{3} \) simplifies to zero when \(m\) is of the form \(4k-1\).
4Step 4: Check Symmetric Properties
Since we are given that the entire expression equals zero, it is crucial to find conditions where this symmetry repeats. When \(m\) is a multiple of 4 minus 1, that is \(m = 4k-1\), the symmetry leads to these sums cancelling out throughout.
5Step 5: Finding the Correct Solution
Test the condition for each choice: (A) \(4k\), (B) \(4k+1\), (C) \(4k-1\), (D) \(4k+2\). Only \(4k-1\) gives the required property where each group of terms sums to zero.
Key Concepts
Binomial CoefficientsCombinatoricsSymmetric Properties
Binomial Coefficients
In mathematics, binomial coefficients are the numbers that appear in the expansion of a binomial raised to a power, written as \((a + b)^m\). These coefficients are represented as \( { }^m C_n \) or \( \binom{m}{n} \) and they have various properties that make them particularly useful.
One important property is that they actually count the number of ways to choose \(n\) items from \(m\) items, and hence they are quite central to combinatorics, as we will see further.
Binomial coefficients can be calculated using the formula:
One important property is that they actually count the number of ways to choose \(n\) items from \(m\) items, and hence they are quite central to combinatorics, as we will see further.
Binomial coefficients can be calculated using the formula:
- \( { }^m C_n = \frac{m!}{n!(m-n)!} \)
Combinatorics
Combinatorics is a field of mathematics focused on counting, arranging, and understanding the patterns within sets. It is directly related to binomial coefficients because these coefficients count the possible combinations of selecting items.
For our expression, which involves alternating sums and differences of binomial coefficients, combinatorial insights help discern how groupings contribute to overall symmetry.
The expression
For our expression, which involves alternating sums and differences of binomial coefficients, combinatorial insights help discern how groupings contribute to overall symmetry.
The expression
- \(\left( { }^{m} C_{0} + { }^{m} C_{1} - { }^{m} C_{2} - { }^{m} C_{3} \right)\)
Symmetric Properties
Symmetric properties are fundamental in understanding why certain combinations of binomial coefficients lead to results of zero. In this problem, by acknowledging that the expression is symmetric, we infer patterns that result in a repeated cancelation for specific values of \(m\).
When \(m = 4k-1\), the cumulative effect of the symmetrical properties is that all groups of coefficients sum to zero. This symmetry stems from how the coefficients are structured across the sequence.
When \(m = 4k-1\), the cumulative effect of the symmetrical properties is that all groups of coefficients sum to zero. This symmetry stems from how the coefficients are structured across the sequence.
- For example, each group is of the form \( { }^{m} C_{4k} + { }^{m} C_{4k+1} - { }^{m} C_{4k+2} - { }^{m} C_{4k+3} \)
Other exercises in this chapter
Problem 62
If coefficient of \(x^{n}\) in \((1+x)^{101}\left(1-x+x^{2}\right)^{100}\) is nonzero, then \(n\) cannot be of the form (A) \(3 t+1\) (B) \(3 t\) (C) \(3 t+2\)
View solution Problem 63
The digit at unit's place in the number \(17^{1995}+11^{1995}\) \(-7^{1995}\) is (A) 0 (B) 1 (C) 2 (D) 3
View solution Problem 67
Let \(n(>1)\) be a positive integer. Then, largest integer \(m\) such that \(\left(n^{\mathrm{m}}+1\right)\) divides \(1+n+n^{2}+\ldots+n^{255}\) is (A) 128 (B)
View solution Problem 68
The value of \(2\left({ }^{n} C_{0}\right)+\frac{3}{2}\left({ }^{-} C_{1}\right)+\frac{4}{3}\left({ }^{-} C_{2}\right)+\frac{5}{4}\left({ }^{-} C_{3}\right) \ld
View solution