Problem 66
Question
In Exercises 59 - 66, find the indicated \( n \)th partial sum of the arithmetic sequence. \( a_1 = 15, a_{100} = 307, n = 100 \)
Step-by-Step Solution
Verified Answer
The 100th partial sum of the given arithmetic sequence is 16100
1Step 1: Identify known values
From the question, we can identify the known values. Here, \(a_1 = 15\), \(a_{100} = 307\), and \(n = 100\).
2Step 2: Substitute into formula for nth partial sum
As per the formula \(S_n = n/2 * (a_1 + a_n)\), we substitute the known values into the formula: \(S_{100} = 100/2 * (15 + 307)\).
3Step 3: Simplify the equation
In this step, we will perform the operations as per BODMAS rule (Bracket, Of, Division, Multiplication, Addition, and Subtraction). Here, sum of first and last terms is \(15 + 307 = 322\), then division by 2 gives \(100/2=50\). On multiplication of these results, we get \(50 * 322 = 16100\).
4Step 4: Conclusion
After all the calculations, \(S_{100} = 16100\). This means that the sum of the first 100 terms of the arithmetic sequence is 16100.
Key Concepts
Partial SumNth TermSequence Formula
Partial Sum
To understand the concept of the partial sum in an arithmetic sequence, start by considering what a sequence is. An arithmetic sequence is a list of numbers where each term after the first is obtained by adding a constant difference to the previous term. The partial sum, denoted as \( S_n \), is the sum of the first \( n \) terms of this sequence.
The formula used to calculate the partial sum in an arithmetic sequence is:
In our example, \( S_{100} = \frac{100}{2} (15 + 307) \) results in 16100, illustrating how partial sums make it straightforward to calculate the total sum of a specified number of terms.
The formula used to calculate the partial sum in an arithmetic sequence is:
- \( S_n = \frac{n}{2} (a_1 + a_n) \)
In our example, \( S_{100} = \frac{100}{2} (15 + 307) \) results in 16100, illustrating how partial sums make it straightforward to calculate the total sum of a specified number of terms.
Nth Term
The n-th term of an arithmetic sequence represents any term located at a position \( n \) in the sequence. Each term is computed from the first term and the common difference \( d \), according to the formula:
Understanding this formula helps in locating any specific term in the sequence without needing to know all preceding terms. In the given problem, we're told that \( a_{100} = 307 \), showing how this term fits within the sequence. Using these portions of information helps verify the structure and correctness of the arithmetic sequence as a whole.
- \( a_n = a_1 + (n-1) \, d \)
Understanding this formula helps in locating any specific term in the sequence without needing to know all preceding terms. In the given problem, we're told that \( a_{100} = 307 \), showing how this term fits within the sequence. Using these portions of information helps verify the structure and correctness of the arithmetic sequence as a whole.
Sequence Formula
The sequence formula is fundamental for arithmetic sequences as it guides how each succeeding term is formed. This formula, \( a_n = a_1 + (n-1) \times d \), is essential for discovering the value of any term in an arithmetic sequence.
Here:
Here:
- \( a_n \) represents the \( n \)th term.
- \( a_1 \) is the first term of the sequence.
- \( d \) is the constant difference between consecutive terms.
- \( n \) is the position of the term in the sequence.
Other exercises in this chapter
Problem 66
In Exercises 65 - 72, write the first six terms of the sequence beginning with the given term. Then calculate the first and second differences of the sequence.
View solution Problem 66
In Exercises 61 - 66, use a graphing utility to graph the first 10 terms of the sequence. \( a_n 10\left(1.2\right)^{n - 1} \)
View solution Problem 66
In Exercises 63-66, write the first five terms of the sequence defined recursively. \( a_1 = 32, a_{k + 1} = \dfrac{1}{2} a_k \)
View solution Problem 67
American roulette is a game in which a wheel turns on a spindle and is divided into \( 38 \) pockets.Thirty-six of the pockets are numbered \( 1-36 \), of which
View solution