Problem 66
Question
Find the center and radius of the circle. $$ (x-5)^{2}+y^{2}=19 $$
Step-by-Step Solution
Verified Answer
Center: (5, 0); Radius: \(\sqrt{19}\).
1Step 1: Identify the Standard Form of a Circle Equation
The equation of a circle in the standard form is given by \((x-h)^2 + (y-k)^2 = r^2\) where \(h, k\) is the center of the circle and \(r\) is the radius. In this form, \(h\) and \(k\) are the x and y coordinates of the circle's center, respectively.
2Step 2: Compare Given Equation with Standard Form
The given equation is \(x - 5\)^2 + y^2 = 19\. Comparing this with the standard form, we find that \(h = 5\) and \(k = 0\). Thus, the center of the circle is \(h, k = (5, 0)\).
3Step 3: Find the Radius of the Circle
From the standard form equation, \(r^2 = 19\). Therefore the radius \(r\) is found by taking the square root of 19, that is \( r = \sqrt{19}.\)
4Step 4: State the Solution
The center of the circle is at (5, 0) and the radius of the circle is \(\sqrt{19}\).
Key Concepts
Center of a CircleRadius of a CircleStandard Form of a Circle
Center of a Circle
The center of a circle is a crucial point that defines its exact location in a plane. Think of it as the circle's "heart," from which every point on the boundary is equidistant.
To find the center from an equation in the standard form,
Thus, the center is located at the point (5, 0).
This point is key to understanding the circle's position and helping us plot it accurately on a graph.
To find the center from an equation in the standard form,
- look at the values of \(h\) and \(k\) in \((x-h)^2 + (y-k)^2 = r^2\).
Thus, the center is located at the point (5, 0).
This point is key to understanding the circle's position and helping us plot it accurately on a graph.
Radius of a Circle
The radius of a circle is the distance from its center to any point on the edge, consistently the same all around.
In the standard form of the circle's equation, this is represented by \(r\) in
Understanding the radius is key to determining the size of the circle.
Although \(\sqrt{19}\) is not an integer, it tells us how large the circle is and how far points on its boundary are from its center.
In the standard form of the circle's equation, this is represented by \(r\) in
- \((x-h)^2 + (y-k)^2 = r^2\).
Understanding the radius is key to determining the size of the circle.
Although \(\sqrt{19}\) is not an integer, it tells us how large the circle is and how far points on its boundary are from its center.
Standard Form of a Circle
The standard form of a circle is an algebraic way to represent all the points that make up the circle. It makes understanding and identifying the circle's key features easy.
The general format is:
By comparing any circle equation to this form, you can quickly extract useful information about its center and size. This makes it an invaluable tool in both geometry and algebra, enabling students to transition easily between equations and visual representations.
The general format is:
- \((x-h)^2 + (y-k)^2 = r^2\)
By comparing any circle equation to this form, you can quickly extract useful information about its center and size. This makes it an invaluable tool in both geometry and algebra, enabling students to transition easily between equations and visual representations.
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