Problem 66
Question
Find exact values of the six trigonometric functions for each angle by hand. Do not use a calculator. $$420^{\circ}$$
Step-by-Step Solution
Verified Answer
The six trigonometric functions for \(420^{\circ}\) are: \(\sin = \frac{\sqrt{3}}{2}\), \(\cos = \frac{1}{2}\), \(\tan = \sqrt{3}\), \(\csc = \frac{2\sqrt{3}}{3}\), \(\sec = 2\), \(\cot = \frac{\sqrt{3}}{3}\).
1Step 1: Determine the Reference Angle
First, we need to find the reference angle for \(420^{\circ}\). Since a full circle is \(360^{\circ}\), we can subtract \(360^{\circ}\) from \(420^{\circ}\) to get the reference angle. \(420^{\circ} - 360^{\circ} = 60^{\circ}\). Thus, the reference angle is \(60^{\circ}\).
2Step 2: Identify the Quadrant
Since \(420^{\circ}\) is equivalent to \(60^{\circ}\), we need to determine in which quadrant \(420^{\circ}\) lies. To do this, observe that \(420^{\circ}\) can be divided into a full rotation of \(360^{\circ}\) plus an additional \(60^{\circ}\), placing it in the first quadrant.
3Step 3: Find Trigonometric Values for \(60^{ ext{o}}\)
In the first quadrant, the trigonometric values for \(60^{\circ}\) are:- \( \sin(60^{\circ}) = \frac{\sqrt{3}}{2} \)- \( \cos(60^{\circ}) = \frac{1}{2} \)- \( \tan(60^{\circ}) = \sqrt{3} \)Since \(420^{\circ}\) is in the first quadrant and equivalent to \(60^{\circ}\), the values are the same for sine, cosine, and tangent.
4Step 4: Derive Reciprocal Functions
Now we find the reciprocal trigonometric functions:- \( \csc(60^{\circ}) = \frac{2}{\sqrt{3}} = \frac{2\sqrt{3}}{3} \)- \( \sec(60^{\circ}) = 2 \)- \( \cot(60^{\circ}) = \frac{1}{\sqrt{3}} = \frac{\sqrt{3}}{3} \)
Key Concepts
Reference AngleQuadrantsReciprocal Trigonometric Functions
Reference Angle
When considering angles beyond one full turn of a circle, like our example angle of \(420^{\circ}\), the reference angle becomes very useful. The reference angle is essentially the smallest angle that the given angle shares with the x-axis. This can always be found by:
- Subtracting \(360^{\circ}\) from your angle until you are in the range of \(0^{\circ} \leq \text{angle} \leq 360^{\circ}\).
- In the case of \(420^{\circ}\), we subtract \(360^{\circ}\) once and end up with \(60^{\circ}\).
Quadrants
The 'quadrant' refers to one of the four sections of the coordinate plane in which an angle can terminate. When analyzing an angle, knowing its quadrant can tell us the signs (positive or negative) of its trigonometric functions. Here's how:
- The first quadrant (\(0^{\circ}\) to \(90^{\circ}\)): all trigonometric functions are positive here.
- The second quadrant (\(90^{\circ}\) to \(180^{\circ}\)): sine is positive, cosine and tangent are negative.
- The third quadrant (\(180^{\circ}\) to \(270^{\circ}\)): tangent is positive, sine and cosine are negative.
- The fourth quadrant (\(270^{\circ}\) to \(360^{\circ}\)): cosine is positive, sine and tangent are negative.
Reciprocal Trigonometric Functions
In addition to the primary trigonometric functions, we have their reciprocals: cosecant, secant, and cotangent. Understanding these is crucial for solving more complex trigonometry problems.
- Cosecant \((\csc)\) is the reciprocal of sine: \( \csc(\theta) = \frac{1}{\sin(\theta)} \).
- Secant \((\sec)\) is the reciprocal of cosine: \( \sec(\theta) = \frac{1}{\cos(\theta)} \).
- Cotangent \((\cot)\) is the reciprocal of tangent: \( \cot(\theta) = \frac{1}{\tan(\theta)} \).
- \(\csc(60^{\circ}) = \frac{2\sqrt{3}}{3}\)
- \(\sec(60^{\circ}) = 2\)
- \(\cot(60^{\circ}) = \frac{\sqrt{3}}{3}\)
Other exercises in this chapter
Problem 66
Graph each function over a two-period interval. $$y=\cot \left(2 x-\frac{3 \pi}{2}\right)$$
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Convert each degree measure to radians. Leave answers as rational multiples of \(\pi .\) $$90^{\circ}$$
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Use the appropriate reciprocal identity to find each firnction value. Rarionalize denominators when applicable. $$\sec \theta, \text { given that } \cos \theta=
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Graph each function over a two-period interval. $$y=1+\tan x$$
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