Problem 66
Question
Find each indicated product. Remember the shortcut for multiplying binomials and the other special patterns we discussed in this section. $$(x+1)^{3}$$
Step-by-Step Solution
Verified Answer
The product \\(x+1\\)^{3} expands to \\(x^3 + 3x^2 + 3x + 1\\).
1Step 1: Recognize the Expression Pattern
The given expression \(x+1\)^{3} is a cube of a binomial. We will use the binomial theorem or the special cube expansion formula to simplify it.
2Step 2: Recall the Binomial Cube Expansion Formula
The cube of a binomial \(a + b\)^3 is expanded using the formula: \(a^3 + 3a^2b + 3ab^2 + b^3\). Here, \a = x\ and \b = 1\.
3Step 3: Substitute and Simplify Terms
Substitute \a = x\ and \b = 1\ into the formula: \(x^3 + 3x^2 \cdot 1 + 3x \cdot 1^2 + 1^3\). Calculate each term separately:1. \x^3\ is \x^3\.2. \3x^2 \cdot 1 = 3x^2\.3. \3x \cdot 1^2 = 3x\.4. \1^3 = 1\.
4Step 4: Write Final Expanded Form
Combine all the terms:\(x^3 + 3x^2 + 3x + 1\). This is the expanded form of \(x+1\)^{3}.
Key Concepts
Binomial ExpansionCube of a BinomialAlgebraic Expressions
Binomial Expansion
Binomial expansion is a mathematical method used to expand expressions that are raised to a power. When you see something like \((a + b)^n\),you're dealing with a binomial expression to the power of\(n\).The binomial theorem provides a powerful formula to help expand these expressions without multiplying them out the long way.
- Essentially, binomial expansion allows us to break down binomials elevated to any specified power.
- This is especially useful for simplifying or calculating polynomial expressions.
Cube of a Binomial
Cubing a binomial refers to raising a binomial expression to the third power. The expression \((a + b)^3\)can be expanded in a special way without needing to multiply manually three times.
For instance, when cubing \((x + 1)\),you substitute\(a = x\) and\(b = 1\)to get:\[x^3 + 3x^2 \cdot 1 + 3x \cdot 1^2 + 1^3.\]After simplifying each term, the expanded form for this binomial is:\(x^3 + 3x^2 + 3x + 1.\)
- The binomial cube expansion formula is given as:\(a^3 + 3a^2b + 3ab^2 + b^3.\)
- This formula is derived from either using the binomial theorem or repeated multiplication.
- The expanded form of cubing a binomial includes four terms, each systematically calculated.
For instance, when cubing \((x + 1)\),you substitute\(a = x\) and\(b = 1\)to get:\[x^3 + 3x^2 \cdot 1 + 3x \cdot 1^2 + 1^3.\]After simplifying each term, the expanded form for this binomial is:\(x^3 + 3x^2 + 3x + 1.\)
Algebraic Expressions
Algebraic expressions are combinations of variables, numbers, and at least one arithmetic operation like addition, subtraction, multiplication, or division. They form the basis for many algebra problems and solutions.
Understanding how to work with algebraic expressions is crucial because it allows us to solve and simplify many types of equations. Mastery of these expressions strengthens mathematical problem-solving skills and aids in comprehending more complex mathematical concepts.
- Expressions such as \((x + 1)\)are considered algebraic because they use variables (like\(x\)).
- When algebraic expressions are combined through operations, they become more complex, such as \((x + 1)^3\).
Understanding how to work with algebraic expressions is crucial because it allows us to solve and simplify many types of equations. Mastery of these expressions strengthens mathematical problem-solving skills and aids in comprehending more complex mathematical concepts.
Other exercises in this chapter
Problem 66
Find all real number solutions for each equation. $$54-6 x^{2}=0$$
View solution Problem 66
Solve each of the equations. $$x^{2}+9 x=0$$
View solution Problem 66
Find each quotient. $$\frac{-32 x^{4} y^{5} z^{8}}{x^{2} y z^{3}}$$
View solution Problem 66
Simplify by removing the inner parentheses first and working outward. $$3 x^{2}-\left[4 x^{2}-2 x-\left(x^{2}-2 x+6\right)\right]$$
View solution