Problem 66
Question
Find an equation of a parabola that satisfies the given conditions. Horizontal axis, vertex \((-1,2),\) passing through \((2,3)\)
Step-by-Step Solution
Verified Answer
The equation is \((y - 2)^2 = \frac{1}{3}(x + 1)\).
1Step 1: Identify the Equation Form
For a parabola with a horizontal axis, the standard form is expressed as \[(y - k)^2 = 4p(x - h)\] where \((h, k)\) is the vertex of the parabola. In this problem, the vertex is given as \((-1, 2)\).
2Step 2: Substitute the Vertex Coordinates
Insert the vertex coordinates \((-1, 2)\) into the standard form:\[(y - 2)^2 = 4p(x + 1)\].
3Step 3: Use Point to Solve for 'p'
The parabola passes through the point \((2, 3)\). Substitute \(x = 2\) and \(y = 3\) into the equation to find \(p\):\[(3 - 2)^2 = 4p(2 + 1)\]\[1 = 12p\]Solving for \(p\), you get \(p = \frac{1}{12}\).
4Step 4: Write the Equation
Plug the value of \(p\) back into the equation:\[(y - 2)^2 = \frac{4}{12}(x + 1)\]Simplifying, the equation of the parabola is:\[(y - 2)^2 = \frac{1}{3}(x + 1)\].
Key Concepts
Vertex FormHorizontal AxisCoordinate Geometry
Vertex Form
Understanding the vertex form of a parabola is crucial when dealing with quadratic equations, especially when the parabola's orientation changes. This form is different based on the axis of symmetry it follows. For a parabola with a horizontal axis of symmetry, the vertex form of the equation is given as:
- \[(y - k)^2 = 4p(x - h)\]
- Vertex \( (h, k) \): This point indicates the peak or lowest point of the parabola, depending on its orientation.
- Focus Parameter \( p \): This determines the distance between the vertex and the focus, directly affecting the parabola's width.
Horizontal Axis
The horizontal axis defines a unique orientation of a parabola, which alters the typical "up" or "down" opening commonly seen in most introductory parabola discussions. When a parabola has a horizontal axis of symmetry, it opens to the right or left depending on the position of the focus relative to the vertex. This means the x-values affect the way the parabola stretches or compresses.
- In a horizontal orientation, the positions of the x and y terms in the formula are switched from the typical vertical forms you might know.
- Imagine the U-shape of a vertical parabola, but lying on its side. It's distinctive, as the y-values now determine the vertex horizontally.
- This kind of parabola is characterized by having its squared term as \( (y - k)^2 \), which signifies y-values being pivotal in stretching the shape horizontally.
Coordinate Geometry
Coordinate geometry is a powerful tool in understanding the properties and equations of shapes like parabolas in a given plane. By using coordinates, you can precisely define the shape, orientation, and size of geometric figures, essential for solving problems in algebra and calculus.
- Point-Slope Relationships: The coordinates of the vertex and other points (like those on the parabola) help in forming equations that reflect real-world shapes.
- Substitution Method: By substituting values into the equation, such as finding \(p\) when given an extra point, you solidify the parabola's equation with precision.
- Visualizing Movement: Understanding coordinates means you can move shapes around a graph seamlessly without losing their structural integrity, which is vital for solving geometric transformations.
Other exercises in this chapter
Problem 65
Find an equation of a parabola that satisfies the given conditions. Horizontal axis, vertex \((-2,3),\) passing through \((-4,0)\)
View solution Problem 65
Solve the system of equations. Give graphical support by making a sketch. $$ \begin{aligned} &\frac{x^{2}}{4}+\frac{y^{2}}{9}=1\\\ &x+y=3 \end{aligned} $$
View solution Problem 66
Solve the system of equations. Give graphical support by making a sketch. $$ \begin{aligned} &\frac{x^{2}}{16}+\frac{y^{2}}{25}=1\\\ &-2 x+y=5 \end{aligned} $$
View solution Problem 67
Write the given equation either in the form \((y-k)^{2}=a(x-h)\) or in the form \((x-h)^{2}=a(y-k)\). $$ -2 x=y^{2}+6 x+10 $$
View solution