Problem 66
Question
Find a set of parametric equations to represent the graph of the rectangular equation using (a) \(t=x\) and \((b) t=2-x\) $$x=3 y-2$$
Step-by-Step Solution
Verified Answer
The parametric equations where \(t = x\) are \(x = t\) and \(y = \frac{t + 2}{3}\). The parametric equations where \(t = 2 - x\) are \(x = 2 - t\) and \(y = \frac{t + 4}{3}\).
1Step 1: Solve for \(x\) and \(y\) given \(t = x\)
Given the equation \(x = 3y - 2\) , and parameter \(t = x\). This implies that our parametric equation would be \(x = t\) . To find the value of \(y\) in terms of \(t\), substitute \(t\) for \(x\) in the original equation. So, \(t = 3y - 2\). Solve this equation for \(y\) to get \(y = \frac{t + 2}{3}\) . This gives us the parametric equations when \(t = x\).
2Step 2: Solve for \(x\) and \(y\) given \(t = 2 - x\)
Given the equation \(x = 3y - 2\) , and parameter \(t = 2 - x\). This implies that our parametric equation would be \(x = 2 - t\). To find the value of \(y\) in terms of \(t\), substitute \(2 - t\) for \(x\) in the original equation. So, this gives us \(2 - t = 3y - 2\). Solve this equation for \(y\) to get \(y = \frac{t + 4}{3}\). This gives us the parametric equations when \(t = 2 - x\).
Key Concepts
Rectangular EquationsParameterizationSolving Equations
Rectangular Equations
A rectangular equation is typically written in terms of the two variables, usually known as \(x\) and \(y\). These equations describe curves or graphs on a plane using a direct relationship between these variables. For instance, the rectangular equation \(x = 3y - 2\) represents a line on the Cartesian plane.
To convert this into parametric form, one or both of the variables are expressed as functions of an independent variable, known as the parameter. This parameter often simplifies analysis and manipulation of the equation.
To convert this into parametric form, one or both of the variables are expressed as functions of an independent variable, known as the parameter. This parameter often simplifies analysis and manipulation of the equation.
- This direct relationship allows us to quickly plot or derive properties like slopes and intercepts directly from the equation without extra transformation.
- Rectangular equations form the backbone for defining simple geometric shapes and linear transformations.
Parameterization
Parameterization is the process of expressing a geometric figure or a function in terms of a parameter. This method is particularly useful in converting equations into a form where each coordinate is a separate function of a parameter \(t\). For example, in the exercise, we took the rectangular equation \(x = 3y - 2\) and represented it in parametric form as \(x = t\) and \(y = \frac{t + 2}{3}\) when \(t = x\).
Alternatively, when setting \(t = 2 - x\), we derive another set of parametric equations: \(x = 2 - t\) and \(y = \frac{t + 4}{3}\). Each parameterization provides a different perspective on the same curve or line.
Alternatively, when setting \(t = 2 - x\), we derive another set of parametric equations: \(x = 2 - t\) and \(y = \frac{t + 4}{3}\). Each parameterization provides a different perspective on the same curve or line.
- Parameterization can simplify the calculation of complex curves and is often used in physics and engineering.
- It provides a way to break a curve into its \(x\) and \(y\) components, expressed through a common parameter.
- This approach can highlight relationships and symmetries not initially obvious in the rectangular form.
Solving Equations
Solving equations is the procedure of finding unknown variables that satisfy the equation under given conditions or constraints. In the exercise, given the rectangular equation \(x = 3y - 2\), setting \(t = x\) or \(t = 2-x\) allows us to re-express this relationship in parametric form to find \(y\) in terms of \(t\).
For the case \(t = x\):
For the case \(t = x\):
- Substitute \(t\) into the equation: \(t = 3y - 2\)
- Solve for \(y\) to obtain \(y = \frac{t + 2}{3}\)
- Substitute \(2-t\) for \(x\): \(2 - t = 3y - 2\)
- Solve for \(y\) to obtain \(y = \frac{t + 4}{3}\)
Other exercises in this chapter
Problem 66
Find the distance between the point and the line. $$\begin{array}{cc}\text{Point} && \text{Line} \\ (-2,8) && y=-3 x+2\end{array}$$
View solution Problem 66
After a rotation of axes is used to eliminate the \(x y\) -term from an equation of the form $$A x^{2}+B x y+C y^{2}+D x+E y+F=0$$ the coefficients of the \(x^{
View solution Problem 66
Classify the graph of the equation as a circle, a parabola, an ellipse, or a hyperbola. $$9 x^{2}+4 y^{2}-90 x+8 y+228=0$$
View solution Problem 67
Determine whether the statement is true or false. Justify your answer. The conic represented by the following equation is an ellipse. $$r^{2}=\frac{16}{9-4 \cos
View solution