Problem 66
Question
Factor completely, or state that the polynomial is prime. $$5 x^{3}-45 x$$
Step-by-Step Solution
Verified Answer
The factored form of \(5x^{3} - 45x\) is \(5x(x+3)(x-3)\).
1Step 1: Identify Common Factors
First, look at the terms in the polynomial and identify any common factors. Both terms, \(5x^{3}\) and \(-45x\), have a common factor of \(5x\).
2Step 2: Factor Out the Common Factor
Next, divide every term in the polynomial by this common factor. This means dividing the term \(5x^{3}\) by \(5x\) to get \(x^{2}\), and \(-45x\) by \(5x\) to get \(-9\). This allows to rewrite the polynomial as \(5x(x^{2}-9)\).
3Step 3: Check if Remaining Polynomial Can be Factored Further.
Then, check if the remaining polynomial inside the parentheses can be factored further. \(x^{2}-9\) can be factored into \((x+3)(x-3)\) because it's a difference of squares.
4Step 4: Write Down the Final Factorized Form
Finally, substitute the factorized form \((x+3)(x-3)\) back into our factored polynomial. This gives the final fully factorized form of the polynomial as \(5x(x+3)(x-3)\).
Other exercises in this chapter
Problem 66
simplify each complex rational expression. $$ \frac{x-3}{x-\frac{3}{x-2}} $$
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In Exercises 59–66, perform the indicated operations. Indicate the degree of the resulting polynomial. $$ \left(5 x^{4} y^{2}+6 x^{3} y-7 y\right)-\left(3 x^{4}
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Evaluate each expression in Exercises \(55-66,\) or indicate that the root is not a real number. $$ \sqrt[6]{\frac{1}{64}} $$
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Write each number in decimal notation without the use of exponents. $$ 9.2 \times 10^{2} $$
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