Problem 66
Question
Evaluate the expression. \(\left(\begin{array}{c}100 \\ 2\end{array}\right)\)
Step-by-Step Solution
Verified Answer
The value is 4950.
1Step 1: Understanding the Binomial Coefficient
The expression \( \binom{100}{2} \) is a binomial coefficient, which is used to calculate the number of ways to choose 2 items from a set of 100 items, without regard to the order of selection.
2Step 2: Apply the Binomial Coefficient Formula
The binomial coefficient is calculated using the formula: \[\binom{n}{k} = \frac{n!}{k!(n-k)!}\]In this case, \( n = 100 \) and \( k = 2 \).
3Step 3: Substitute Values into the Formula
Substitute \( n = 100 \) and \( k = 2 \) into the formula:\[\binom{100}{2} = \frac{100!}{2!(100-2)!}\]This simplifies to:\[\frac{100 \times 99 \times 98!}{2 \times 1 \times 98!}\]
4Step 4: Simplify the Expression
Cancel out the \( 98! \) in the numerator and the denominator:\[\frac{100 \times 99}{2 \times 1} = \frac{100 \times 99}{2}\]
5Step 5: Calculate the Final Result
Calculate the result by simplifying the remaining fraction:\[\frac{100 \times 99}{2} = \frac{9900}{2} = 4950\]
Key Concepts
CombinatoricsFactorialsAlgebraic Expressions
Combinatorics
Combinatorics is a fascinating area of mathematics that deals with counting and arranging objects. It helps us find out how many possible ways there are to do something, like arranging books on a shelf or forming a committee. In this context, we're looking at how to choose a specific number of items from a larger set, which is where binomial coefficients come into play.
- Binomial coefficients are a key concept in combinatorics used for understanding combinations.
- They represent the number of ways to choose \( k \) items from \( n \) items without considering the order.
- The expression \( \binom{n}{k} \) is used to denote these combinations.
Factorials
Factorials are instrumental in the calculation of combinations and permutations. The factorial of a number, denoted by \( n! \), is the product of all positive integers up to that number.
- For example, \( 5! = 5 \times 4 \times 3 \times 2 \times 1 = 120 \).
- Factorials build up very quickly, which is both their power and their challenge.
- In binomial coefficients, factorials are used to determine the number of permutations and combinations.
Algebraic Expressions
Algebra involves using symbols and letters to represent numbers and quantities in formulas and equations. In our case, algebra helps simplify the problem, making it easier to solve.
- An algebraic expression like \( \frac{100 \times 99 \times 98!}{2 \times 1 \times 98!} \) looks complex, but algebra allows us to see what can be cancelled or simplified.
- The ability to reduce expressions by cancelling similar terms (like \( 98! \) in both numerator and denominator) demonstrates algebra's power.
- This simplification leads to a manageable expression: \( \frac{100 \times 99}{2} \).
Other exercises in this chapter
Problem 65
Evaluate the expression. \(\left(\begin{array}{c}20 \\ 18\end{array}\right)\)
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Write out the terms of the series and then evaluate it. $$\sum_{k=1}^{7} k^{3}$$
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Write out the terms of the series and then evaluate it. $$\sum_{k=1}^{4} 5(2)^{k-1}$$
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Conditional Probability and Dependent Events Numbers Suppose a number from 1 to 15 is selected at random. Find the probability of each event. A. The number is o
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