Problem 66
Question
Determine whether the infinite geometric series is convergent or divergent. If it is convergent, find its sum. $$1-\frac{1}{2}+\frac{1}{4}-\frac{1}{8}+\cdots$$
Step-by-Step Solution
Verified Answer
The series is convergent with a sum of \(\frac{2}{3}\).
1Step 1: Identify the first term and common ratio
The infinite geometric series is given as \(1 - \frac{1}{2} + \frac{1}{4} - \frac{1}{8} + \cdots\). The first term \(a\) is \(1\), and the common ratio \(r\) can be found by dividing the second term by the first term: \(r = -\frac{1}{2}\).
2Step 2: Determine convergence or divergence
For a geometric series to converge, the common ratio \(|r|\) must be less than 1. In this series, \(|r| = \left| -\frac{1}{2} \right| = \frac{1}{2}\), which is less than 1. Therefore, the series is convergent.
3Step 3: Use the formula for the sum of a convergent series
The sum \(S\) of an infinite geometric series can be calculated with the formula \(S = \frac{a}{1 - r}\), where \(a\) is the first term and \(r\) is the common ratio. Substitute \(a = 1\) and \(r = -\frac{1}{2}\) into the formula: \[ S = \frac{1}{1 - (-\frac{1}{2})} = \frac{1}{1 + \frac{1}{2}} = \frac{1}{\frac{3}{2}} = \frac{2}{3}.\]
Key Concepts
Convergent SeriesInfinite SeriesCommon Ratio
Convergent Series
A convergent series is a series whose terms get closer and closer to a specific value as the number of terms increases. In the context of geometric series, convergence occurs when the series settles into a stable sum. For a geometric series to be convergent, the absolute value of the common ratio must be less than one.
Understanding convergence is important because it helps us determine whether the series has a sum that can be calculated.
- This means that the terms decrease in size and the series approaches a finite limit.
- If \(|r| < 1\), the series is convergent. Otherwise, it is divergent.
Understanding convergence is important because it helps us determine whether the series has a sum that can be calculated.
Infinite Series
An infinite series is essentially the sum of an infinite number of terms. This can initially be an abstract concept because adding up infinitely many numbers hints at an undefined or infinite result. However, some infinite series can indeed have a finite sum, and these are particularly interesting because they challenge our preconception of infinity.
When dealing with a geometric series like \(1 - \frac{1}{2} + \frac{1}{4} - \frac{1}{8} + \cdots\), it’s the behavior dictated by the common ratio that determines the convergence.
When dealing with a geometric series like \(1 - \frac{1}{2} + \frac{1}{4} - \frac{1}{8} + \cdots\), it’s the behavior dictated by the common ratio that determines the convergence.
- If the common ratio signaling a reduction in terms is observed, the series can be summed to a specific value despite being infinite.
- If the series is divergent with \(|r| \geq 1\), it doesn’t settle on a particular sum.
Common Ratio
The common ratio in a geometric series is a vital element that helps determine the nature of the series. It is found by dividing any term in the series by the previous term. This ratio is consistent throughout the series, dictating how successive terms relate.
In the given series, the common ratio \(r\) is \(-\frac{1}{2}\).
In the given series, the common ratio \(r\) is \(-\frac{1}{2}\).
- The formula to find subsequent terms is multiplying the last term by the common ratio.
- Because the \(|r| \) is less than one, we can conclude that this series is convergent.
- The behavior of this ratio, being negative, also causes the series to alternate in sign.
Other exercises in this chapter
Problem 65
Write the sum without using sigma notation. $$\sum_{k=3}^{100} x^{k}$$
View solution Problem 66
Find the number of terms of the arithmetic sequence with the given description that must be added to get a value of 2700. The first term is \(12,\) and the comm
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Write the sum without using sigma notation. $$\sum_{j=1}^{n}(-1)^{j+1} x^{j}$$
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Show that a right triangle whose sides are in arithmetic progression is similar to a \(3-4-5\) triangle.
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