Problem 66
Question
Determine any point(s) of intersection algebraically. Then verify your result numerically by creating a table of values for each function. $$\begin{aligned} &x-y=-4\\\ &x+2 y=5 \end{aligned}$$
Step-by-Step Solution
Verified Answer
The point of intersection of the functions is \((1,3)\). The tables for \(x−y=−4\) and \(x+2y=5\), at \(x=1\) proved to be equal to \(y=3\), confirming the results.
1Step 1: Solve one of the equations for one variable
Solve the first equation for \(x\). Rearrange the first equation to read: \(x = y - 4\).
2Step 2: Substitute the solved equation into the second equation
Replace \(x\) from second equation with \(y - 4\) getting: \(y - 4 + 2y = 5\). From here, simplify the equation to find the value of \(y\).
3Step 3: Solve for the other variable
Solve for \(y\) to get \(y = 3\). Now substiute \(y = 3\) into the first original equation to find the corresponding \(x\) value.
4Step 4: Verify with a table
Once point of intersection is found, create tables for each equation and confirm if at \(x = 1\) each function yields a \(y\) value of 3.
Key Concepts
Point of IntersectionSubstitution MethodAlgebraic VerificationTable of Values
Point of Intersection
When two lines cross on a graph, the spot where they meet is the point of intersection.
For this problem, the point of intersection is where both equations share the same values of and for their variables.
To find it, we first need to determine the values of x and y that satisfy both equations:
This point is essential in various scenarios since it indicates where two situations or datasets behave the same way.
For this problem, the point of intersection is where both equations share the same values of and for their variables.
To find it, we first need to determine the values of x and y that satisfy both equations:
- Equation 1: \( x - y = -4 \)
- Equation 2: \( x + 2y = 5 \)
This point is essential in various scenarios since it indicates where two situations or datasets behave the same way.
Substitution Method
The substitution method is a common strategy used to solve systems of equations.
Here's a quick guide:
Next, replace "x" in the second equation with \( y + 4 \), leading to \( (y + 4) + 2y = 5 \).
Simplify this to find \( y = 3 \).
This method effectively reduces the number of variables, making it manageable to find their actual values.
Here's a quick guide:
- Solve one equation for one variable.
- Substitute this expression into the other equation.
- Simplify and solve for the remaining variable.
Next, replace "x" in the second equation with \( y + 4 \), leading to \( (y + 4) + 2y = 5 \).
Simplify this to find \( y = 3 \).
This method effectively reduces the number of variables, making it manageable to find their actual values.
Algebraic Verification
After finding the potential solution for the system, it's crucial to verify it to avoid errors.
Algebraic verification involves plugging the found values back into the original equations:
This step ensures that no algebraic mistakes were made and confirms the result's accuracy.
Algebraic verification involves plugging the found values back into the original equations:
- Equation 1: Substitute \( x = 1 \) and \( y = 3 \): \( 1 - 3 = -4 \). It holds true.
- Equation 2: Substitute \( x = 1 \) and \( y = 3 \): \( 1 + 2(3) = 1 + 6 = 5 \). It holds true.
This step ensures that no algebraic mistakes were made and confirms the result's accuracy.
Table of Values
Creating a table of values is a practical way to verify the solution by testing few x values.
You make columns for x and y, then plot each equation using simple substitutions.
In these tables:
Tables visually confirm our solution, enhancing our confidence in its correctness.
You make columns for x and y, then plot each equation using simple substitutions.
In these tables:
- Equation 1: Choose x-values, calculate corresponding y by solving \( y = x + 4 \).
- Equation 2: Use the same x-values, find y by solving \( y = \frac{5-x}{2} \).
- Equation 1 gives y = 1 + 4 = 5
- Equation 2 gives y = (5-1)/2 = 2
Tables visually confirm our solution, enhancing our confidence in its correctness.
Other exercises in this chapter
Problem 66
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