Problem 66
Question
Convert the polar equation to rectangular form. $$r=2 \cos \theta$$
Step-by-Step Solution
Verified Answer
The rectangular form of the given polar equation is \(x^2 - 2x + y^2 = 0\).
1Step 1: Apply the Polar to Rectangular Conversion Formulas
Start by applying the formula for conversion from polar to rectangular coordinates. Specifically, replace r in the given equation with \(x^2 + y^2\). The polar equation is \(r = 2 \cos \theta\). Replacing r gives: \(x^2 + y^2 = 2 \cos \theta\).
2Step 2: Simplify \(\cos \theta\) in rectangular terms
Next, the goal is to express \(\cos \theta\) in terms of x and y. To this end, recall that \(\cos \theta = \frac{x}{r}\), and replace \(\cos \theta\) in the equation obtained in Step 1 by \(\frac{x}{r}\): \(x^2 + y^2 = 2 \frac{x}{\sqrt{x^2 + y^2}}\).
3Step 3: Conversion to rectangular form
Now, simplify the equation from Step 2 to arrive at the equation in rectangular form. First, cross-multiply to eliminate the denominator giving: \(x^2 + y^2 = 2x\). Then, subtract 2x from both sides to isolate the terms: \(x^2 - 2x + y^2 = 0\).
Other exercises in this chapter
Problem 65
Classify the graph of the equation as a circle, a parabola, an ellipse, or a hyperbola. \(x^{2}-6 x-2 y+7=0\)
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Determine whether the equation represents a degenerate conic. Explain. $$16 x^{2}+25 y^{2}-32 x+50 y+16=0$$
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Determine whether the statement is true or false. Justify your answer. Because the graphs of the parametric equations \(x=t^{2}\) \(y=t^{2}\) and \(x=t, y=t\) b
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Find the vertex, focus, and directrix of the parabola and sketch its graph. Use a graphing utility to verify your graph. $$x+y^{2}=0$$
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