Problem 66
Question
59–76 Prove the identity. $$\cot 2 x=\frac{1-\tan ^{2} x}{2 \tan x}$$
Step-by-Step Solution
Verified Answer
Identity is verified as correct.
1Step 1: Recall Trigonometric Identity
We start by recalling the identity for \( \cot 2x \), which is the cotangent of a double angle. The identity is given by:\[ \cot 2x = \frac{1 - \tan^2 x}{2 \tan x} \]This is what we need to prove is equal to \( \frac{1 - \tan^2 x}{2 \tan x} \). We will verify this equation step by step.
2Step 2: Use Double Angle Identity for Tangent
The double angle identity for tangent is:\[ \tan(2x) = \frac{2 \tan x}{1 - \tan^2 x} \]Knowing that \( \cot \theta = \frac{1}{\tan \theta} \), the cotangent double angle identity is:\[ \cot(2x) = \frac{1}{\tan(2x)} = \frac{1 - \tan^2 x}{2 \tan x} \]
3Step 3: Verify and Simplify
To verify, find the expression \( \cot(2x) \) using the identity derived.Since \( \cot(2x) = \frac{1}{\tan(2x)} \), substituting the expression for \( \tan(2x) \), we have:\[ \cot(2x) = \frac{1}{\frac{2 \tan x}{1 - \tan^2 x}} = \frac{1 - \tan^2 x}{2 \tan x} \]This confirms the given identity.
Key Concepts
Understanding CotangentExploring Double Angle FormulasThe Role of Tangent in Trigonometry
Understanding Cotangent
Cotangent, often written as \( \cot \), is one of the six fundamental trigonometric functions. It is closely related to the tangent function. In terms of a right triangle, cotangent for an angle \( \theta \) is defined as the ratio of the adjacent side to the opposite side. Mathematically, this can be represented as:
In the example problem, \( \cot(2x) \) was derived to establish a specific identity. Using known identities and step-by-step verification helps to fully grasp the concept of cotangent and how it interlinks with other trigonometric functions.
- \( \cot \theta = \frac{1}{\tan \theta} \)
- \( \cot \theta = \frac{\text{Adjacent}}{\text{Opposite}} \)
In the example problem, \( \cot(2x) \) was derived to establish a specific identity. Using known identities and step-by-step verification helps to fully grasp the concept of cotangent and how it interlinks with other trigonometric functions.
Exploring Double Angle Formulas
Double angle formulas are essential tools in trigonometry, used to simplify expressions involving angles that are doubled. For sine, cosine, and tangent, these formulas help reveal relationships within trigonometric functions when the angle is multiplied by two.
Here are the common double angle formulas:
Here are the common double angle formulas:
- \( \sin(2x) = 2 \sin x \cos x \)
- \( \cos(2x) = \cos^2 x - \sin^2 x = 2 \cos^2 x - 1 = 1 - 2 \sin^2 x \)
- \( \tan(2x) = \frac{2 \tan x}{1 - \tan^2 x}\)
The Role of Tangent in Trigonometry
Tangent, like sine and cosine, is a fundamental trigonometric function. It’s usually defined as the ratio of the sine to the cosine of an angle, \( \theta \). In the context of a right triangle, \( \tan \theta \) can be described as the ratio of the opposite side to the adjacent side:
Proper utilization of tangent is necessary for the transition from the expression of one trigonometric function to another. This manipulation allows for the proof of identities, such as the one provided in the exercise. Recognizing the interplay between tangent and cotangent, especially when working with double angles, is key to mastering these concepts.
- \( \tan \theta = \frac{\sin \theta}{\cos \theta} \)
- \( \tan \theta = \frac{\text{Opposite}}{\text{Adjacent}} \)
Proper utilization of tangent is necessary for the transition from the expression of one trigonometric function to another. This manipulation allows for the proof of identities, such as the one provided in the exercise. Recognizing the interplay between tangent and cotangent, especially when working with double angles, is key to mastering these concepts.
Other exercises in this chapter
Problem 66
Verify the identity. $$ \frac{1-\cos x}{\sin x}+\frac{\sin x}{1-\cos x}=2 \csc x $$
View solution Problem 66
Use a double-or half-angle formula to solve the equation in the interval \([0,2 \pi) .\) $$\tan \frac{x}{2}-\sin x=0$$
View solution Problem 67
Verify the identity. $$ \frac{\csc x-\cot x}{\sec x-1}=\cot x $$
View solution Problem 67
Use a double-or half-angle formula to solve the equation in the interval \([0,2 \pi) .\) $$\cos 2 x+\cos x=2$$
View solution