Problem 66
Question
\(15 d-(6 d+1)-d\)
Step-by-Step Solution
Verified Answer
The simplified expression is \(8d - 1\).
1Step 1: Simplify Inside the Parentheses
First, simplify the expression inside the parentheses. The expression is \(6d + 1\).
2Step 2: Distribute the Negative Sign
Next, distribute the negative sign from \(-(6d + 1)\) to each term inside the parentheses: \(-(6d + 1) = -6d - 1\).
3Step 3: Rewrite the Expression
Rewrite the original expression by replacing \(-(6d + 1)\) with \(-6d - 1\): \(15d - 6d - 1 - d\).
4Step 4: Combine Like Terms
Combine the like terms. This involves adding or subtracting the coefficients of the same variable:\(15d - 6d - d = 8d\). The resulting expression is \(8d - 1\).
Key Concepts
Distributive PropertyCombining Like TermsAlgebraic Expressions
Distributive Property
The distributive property is a valuable algebraic tool, essential for solving various expressions. It allows you to multiply a single term across terms within parentheses.
For instance, in the exercise: \(15d - (6d + 1) - d\), the distributive property helps when we deal with \(-(6d + 1)\). Here's why:
It’s a crucial process that makes expressions manageable and prepares them for further simplification.
For instance, in the exercise: \(15d - (6d + 1) - d\), the distributive property helps when we deal with \(-(6d + 1)\). Here's why:
- This means you multiply \(-1\) by each term in the parentheses.
It’s a crucial process that makes expressions manageable and prepares them for further simplification.
Combining Like Terms
Combining like terms is all about making expressions simpler.
Like terms are terms that have the same variable and exponent. They can be combined by adding or subtracting their coefficients. In the improved expression \(15d - 6d - 1 - d\), we have:
Like terms are terms that have the same variable and exponent. They can be combined by adding or subtracting their coefficients. In the improved expression \(15d - 6d - 1 - d\), we have:
- \(15d - 6d - d\)
- First, add \(15d\) and \(-6d\), which gives \(9d\).
- Then, subtract \(d\) from \(9d\), resulting in \(8d\).
Algebraic Expressions
Algebraic expressions are a fundamental concept in algebra.
They consist of numbers, variables, and operations (such as addition and subtraction). Our exercise deals with this expression: \(15d - (6d + 1) - d\). Breaking down complex expressions is key in algebra:
Understanding how to manipulate and simplify them is essential for tackling more advanced problems later on.
They consist of numbers, variables, and operations (such as addition and subtraction). Our exercise deals with this expression: \(15d - (6d + 1) - d\). Breaking down complex expressions is key in algebra:
- First, deal with the parentheses using the distributive property.
- Second, rewrite the expression by combining simplified parts.
- Third, combine like terms to further reduce the expression.
Understanding how to manipulate and simplify them is essential for tackling more advanced problems later on.
Other exercises in this chapter
Problem 66
A restaurant bill is \(\$ 65\). If the tip is \(20 \%\) of the bill, find the total cost of the meal including tip.
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\(24-3(10)\)
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The original price of a computer is \(\$ 899\). If it is marked down \(23 \%\), find the sale price.
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