Problem 65 - Chemistry: The Central Science

Question

Write balanced equations for the following reactions: (a) barium oxide with water, (b) iron(II) oxide with perchloric acid, (c) sulfur trioxide with water, (d) carbon dioxide with aqueous sodium hydroxide.

Step-by-Step Solution

Answer

Here are the balanced equations for each reaction: (a) Barium oxide with water: \( BaO + H_2O \rightarrow Ba(OH)_2 \) (b) Iron(II) oxide with perchloric acid: \( 2FeO + 2HClO_4 \rightarrow 2Fe(ClO_4)_2 + 2H_2O \) (c) Sulfur trioxide with water: \( SO_3 + H_2O \rightarrow H_2SO_4 \) (d) Carbon dioxide with aqueous sodium hydroxide: \( CO_2 + 2NaOH \rightarrow Na_2CO_3 + H_2O \)

Step 1: Reaction 1: Barium oxide with water

1. Identify reactants and products: Reactants: Barium oxide (BaO) and water (H₂O) Product: Barium hydroxide (Ba(OH)₂) 2. Write the unbalanced equation: BaO + H₂O → Ba(OH)₂ 3. Balance the equation: BaO + H₂O → Ba(OH)₂ (The equation is already balanced with 1:1:1 stoichiometry)

Step 2: Reaction 2: Iron(II) oxide with perchloric acid

1. Identify reactants and products: Reactants: Iron(II) oxide (FeO) and perchloric acid (HClO₄) Products: Iron(II) perchlorate (Fe(ClO₄)₂) and water (H₂O) 2. Write the unbalanced equation: FeO + HClO₄ → Fe(ClO₄)₂ + H₂O 3. Balance the equation: 2FeO + 2HClO₄ → 2Fe(ClO₄)₂ + 2H₂O

Step 3: Reaction 3: Sulfur trioxide with water

1. Identify reactants and products: Reactants: Sulfur trioxide (SO₃) and water (H₂O) Product: Sulfuric acid (H₂SO₄) 2. Write the unbalanced equation: SO₃ + H₂O → H₂SO₄ 3. Balance the equation: SO₃ + H₂O → H₂SO₄ (The equation is already balanced with 1:1:1 stoichiometry)

Step 4: Reaction 4: Carbon dioxide with aqueous sodium hydroxide

1. Identify reactants and products: Reactants: Carbon dioxide (CO₂) and aqueous sodium hydroxide (NaOH) Products: Sodium carbonate (Na₂CO₃) and water (H₂O) 2. Write the unbalanced equation: CO₂ + NaOH → Na₂CO₃ + H₂O 3. Balance the equation: CO₂ + 2NaOH → Na₂CO₃ + H₂O