Problem 65
Question
Von Bertalanffy Growth Model The growth of fish can be described by the von Bertalanffy growth function $$ L(x)=L_{\infty}-\left(L_{\infty}-L_{0}\right) e^{-k x} $$ where \(x\) denotes the age of the fish and \(k, L_{\infty}\), and \(L_{0}\) are positive constants. (a) \(\operatorname{Set} L_{0}=1\) and \(L_{\infty}=10 .\) Graph \(L(x)\) for \(k=1.0\) and \(k=0.1\). (b) Interpret \(L_{\infty}\) and \(L_{0}\). (c) Compare the graphs for \(k=0.1\) and \(k=1.0 .\) According to your graphs which fish reach \(L=5\) more quickly? (d) Show that $$ \frac{d}{d x} L(x)=k\left(L_{\infty}-L(x)\right) $$ That is, \(d L / d x \propto L_{\infty}-L .\) What does this proportionality say about how the rate of growth changes with age? (e) The constant \(k\) is the proportionality constant in (d). What does the value of \(k\) tell you about how quickly a fish grows?
Step-by-Step Solution
VerifiedKey Concepts
Fish Growth
- \(L(x)\) is the length of the fish at age \(x\).
- \(L_{\infty}\) represents the asymptotic length, or the maximum length the fish is expected to reach as it approaches old age.
- \(L_{0}\) is the initial length at the age of 0, or when the fish is just starting out in life.
- \(k\) is the growth rate constant, which influences how quickly the fish reaches its asymptotic size.
Differential Calculus
For the von Bertalanffy growth function, we use differential calculus to find the rate at which fish length, \(L(x)\), changes with respect to its age, \(x\). The derivative of \(L(x)\) is given by\[\frac{dL(x)}{dx} = k(L_{\infty} - L(x))\]Here’s how to interpret this derivative:
- \(\frac{dL(x)}{dx} \) is the rate of change of the fish's length as it ages.
- The equation shows that this rate of change is proportional to the difference between the asymptotic length, \(L_{\infty}\), and the current length, \(L(x)\).
Asymptotic Analysis
To understand this, consider that as a fish ages indefinitely, the term \((L_{\infty} - L_{0}) e^{-kx}\) in the growth function \[ L(x) = L_{\infty} - (L_{\infty} - L_{0}) e^{-kx} \] becomes negligible, making \(L(x)\) approximate \(L_{\infty}\).This shows:
- The asymptotic length \(L_{\infty}\) is the length that the fish approaches but never actually reaches.
- It confirms that for large values of \(x\) (as the fish ages), the exponential term decreases to zero, leaving \(L(x)\) just under \(L_{\infty}\).
- The speed at which this is approached depends on \(k\); a larger \(k\) causes the fish to reach near \(L_{\infty}\) quicker than a smaller \(k\) would.
Exponential Models
The von Bertalanffy growth model incorporates an exponential decay term, \(e^{-kx}\), to account for how rapidly a fish grows as it approaches its asymptotic length.
- This term originates from the nature of biological growth processes where resources and physiological limits like food availability and metabolic rate naturally cap off growth, emphasizing a slowdown as organisms grow larger.
- In the equation, as \(x\) (age) increases, \(e^{-kx}\) decreases, which means that the effect of the initial length becomes trivial, allowing the fish to gradually reach its maximum possible size.
- The value of \(k\) plays a significant role in shaping the curve of the exponential term: a higher \(k\) means the fish grows quickly over a short term and nears its potential length faster.