Problem 65
Question
Use the factor theorem and determine whether the first expression is a factor of \(P(x) .\) See Example 5. $$ x-3 ; P(x)=x^{3}-3 x^{2}+5 x-15 $$
Step-by-Step Solution
Verified Answer
Yes, \(x - 3\) is a factor of \(P(x)\) because \(P(3) = 0\).
1Step 1: Understand the Factor Theorem
The Factor Theorem states that \(x - a\) is a factor of \(P(x)\) if and only if \(P(a) = 0\). This means we need to evaluate \(P(3)\) to see if it equals zero.
2Step 2: Substitute and Evaluate P(x)
Substitute \(x = 3\) in \(P(x) = x^3 - 3x^2 + 5x - 15\). Calculate \(P(3) = 3^3 - 3(3)^2 + 5(3) - 15\).
3Step 3: Perform the Calculations
Compute each term: \(3^3 = 27\), \(3 \times 3^2 = 27\), \(5 \times 3 = 15\). Thus, \(P(3) = 27 - 27 + 15 - 15\).
4Step 4: Simplify the Expression
Simplify the expression \(27 - 27 + 15 - 15\) which results in \(0\).
5Step 5: Conclusion Based on Factor Theorem
Since \(P(3) = 0\), according to the Factor Theorem, \(x - 3\) is a factor of \(P(x)\).
Key Concepts
Understanding PolynomialsBasics of Algebra and Factor TheoremIdentifying Roots of Equations
Understanding Polynomials
Polynomials are mathematical expressions that consist of variables raised to whole number exponents and coefficients. They can take various forms depending on the number and degree of terms they have. In this exercise, we are dealing with a cubic polynomial, which means the highest degree of the variable, in this case, is 3. Hence, the polynomial function can be written as:
Polynomials are essential in algebra, as they form the building blocks for a wide range of calculations, including solving equations and modeling real-world scenarios.
- Cubic Polynomial: This is a polynomial of degree 3. For example, the given polynomial is \( P(x) = x^3 - 3x^2 + 5x - 15 \).
- Terms of a Polynomial: The terms in a polynomial are the individual components separated by either addition or subtraction. In our polynomial, those terms are \(x^3\), \(-3x^2\), \(5x\), and \(-15\).
Polynomials are essential in algebra, as they form the building blocks for a wide range of calculations, including solving equations and modeling real-world scenarios.
Basics of Algebra and Factor Theorem
Algebra helps us in understanding and solving equations symbolically. The Factor Theorem is a critical concept in algebra that connects factors of polynomials to their roots. Let's break this down further:
- Expressions and Equations: Algebra is about finding the unknown values. Expressions like \(x - 3\) are parts of larger equations used to find when a polynomial equals zero.
- Factor Theorem Description: According to the Factor Theorem, \((x - a)\) is a factor of a polynomial \(P(x)\) if and only if substituting \(x = a\) in \(P(x)\) results in zero.
Identifying Roots of Equations
The roots or solutions of polynomials are points where the polynomial equals zero. These are also referred to as the 'zeros' of the polynomial. Finding these roots is an essential step in solving polynomial equations:
This understanding helps to connect the mathematical theory to practical problem solving.
- Roots and Zeros: In the given exercise, by confirming \(P(3) = 0\), we've identified \(x = 3\) as a root of the polynomial.
- Finding Roots Using Factor Theorem: The Factor Theorem allows us to check if \((x - 3)\) is a factor by substituting 3 and confirming it results in zero. Thus, \(x = 3\) is a root.
This understanding helps to connect the mathematical theory to practical problem solving.
Other exercises in this chapter
Problem 64
Divide, and then simplify, if possible. See Example 8. $$ \frac{x-2}{x} \div\left(x^{2}-4\right) $$
View solution Problem 64
Simplify each rational expression. $$ \frac{x^{2}-2 x-15}{25-x^{2}} $$
View solution Problem 65
Solve equation. If a solution is extraneous, so indicate. \(\frac{2}{x}+\frac{1}{2}=\frac{9}{4 x}-\frac{1}{2 x}\)
View solution Problem 65
Simplify each complex fraction. $$ \frac{\frac{2}{y-1}-\frac{2}{y}}{\frac{3}{y-1}-\frac{1}{1-y}} $$
View solution