Problem 65
Question
Use the discriminant to help solve each problem. Determine \(k\) so that \(4 x^{2}-k x+1=0\) has two equal real solutions.
Step-by-Step Solution
Verified Answer
The value of \(k\) is either 4 or -4.
1Step 1: Understand the Problem
To find the value of \(k\) such that the quadratic equation \(4x^2 - kx + 1 = 0\) has two equal real solutions, we need to explore the condition for a quadratic to have equal roots. This occurs when the discriminant is zero.
2Step 2: Recall the Discriminant Formula
For a quadratic equation of the form \(ax^2 + bx + c = 0\), the discriminant \(\Delta\) is given by \(\Delta = b^2 - 4ac\). The roots are equal when \(\Delta = 0\).
3Step 3: Substitute into the Discriminant Formula
In our equation, \(a = 4\), \(b = -k\), and \(c = 1\). Substitute these into the discriminant formula: \[(-k)^2 - 4(4)(1) = 0\].
4Step 4: Simplify the Equation
Simplify the discriminant equation: \[k^2 - 16 = 0\].
5Step 5: Solve for \(k\)
Rearrange the equation to find \(k\): \[k^2 = 16\]. Take the square root of both sides: \[k = \pm 4\].
6Step 6: Conclusion
The equation \(4x^2 - kx + 1 = 0\) has two equal real solutions when \(k = 4\) or \(k = -4\).
Key Concepts
The DiscriminantEqual RootsThe Quadratic Formula
The Discriminant
When solving quadratic equations, the discriminant provides valuable information about the nature of the roots. Its formula is \[ \Delta = b^2 - 4ac \]where
- \(a\), \(b\), and \(c\) represent the coefficients in the quadratic equation \(ax^2 + bx + c = 0\).
- \(b^2\) is the square of the coefficient of \(x\), which impacts how the parabola opens and its vertex.
- \(4ac\) involves both the coefficient of \(x^2\) and the constant term, balancing the quadratic equation.
- If \(\Delta > 0\), there are two distinct real roots.
- If \(\Delta = 0\), there are two equal real roots.
- If \(\Delta < 0\), the roots are complex and not real.
Equal Roots
Equal roots in a quadratic equation occur when the discriminant is zero. This is because having the discriminant equal to zero (\(\Delta = 0\)) eliminates the possibility of distinct or complex roots. In mathematical terms, this situation means \[b^2 - 4ac = 0\]. In this condition:
- The quadratic equation has what is called a 'perfect square trinomial'.
- The graph of the quadratic touches the x-axis at exactly one point, indicating the root's multiplicity of two.
- By substituting the given coefficients into \(\Delta = b^2 - 4ac\), you find:
- \((-k)^2 - 4(4)(1) = 0\) simplifies to \(k^2 - 16 = 0\).
The Quadratic Formula
The quadratic formula is a powerful tool for solving quadratic equations. It is derived directly from the process of completing the square and is applicable to any quadratic equation.The formula is expressed as:\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]This formula computes the roots \(x\) of any quadratic equation \(ax^2 + bx + c = 0\), regardless of the specific values of \(a\), \(b\), or \(c\). Here's how each part functions in finding roots:
- The term \(-b\) adjusts the form to find the middle of the quadratic expression.
- The square root component \(\sqrt{b^2 - 4ac}\) accounts for the separation between roots, linking back to the discriminant's role.
- The division by \(2a\) scales the result to correspond correctly with the quadratic's leading coefficient.
Other exercises in this chapter
Problem 64
For the indicated variable. Assume that all letters represent positive numbers. \(\frac{x^{2}}{a^{2}}-\frac{y^{2}}{b^{2}}=1\) for \(y\)
View solution Problem 64
Find each of the products and express the answers in the standard form of a complex number. $$(-5 i)(-12 i)$$
View solution Problem 65
For the indicated variable. Assume that all letters represent positive numbers. \(\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1\) for \(x\)
View solution Problem 65
Find each of the products and express the answers in the standard form of a complex number. $$(3 i)(2-5 i)$$
View solution