Problem 65
Question
Use a graphing utility to graph \(\frac{x^{2}}{4}-\frac{y^{2}}{9}=0 .\) Is the graph a hyperbola? In general, what is the graph of \(\frac{x^{2}}{a^{2}}-\frac{y^{2}}{b^{2}}=0 ?\)
Step-by-Step Solution
Verified Answer
The graph of \(\frac{x^{2}}{4}-\frac{y^{2}}{9}=0\) is a pair of intersecting lines, not a hyperbola. By generalization, the graph of \(\frac{x^{2}}{a^{2}}-\frac{y^{2}}{b^{2}}=0\) is a hyperbola when \(a ≠ b\) and a pair of intersecting lines when \(a = b\).
1Step 1: Graph the given equation
Use a graphing utility which can handle equations of multiple variables to plot the equation \(\frac{x^{2}}{4}-\frac{y^{2}}{9}=0\). The graphing tool would plot points \((x, y)\) which satisfy this equation.
2Step 2: Analyze the plot
Observe the graph created by the graphing utility. For the given equation, the graph will be a pair of intersecting lines, not a hyperbola. This is because the equation can be simplified as \(x^2 - y^2 = 0\), which further simplifies to \(x = ±y\), representing two intersecting lines instead of a hyperbola.
3Step 3: Generalize to the form of the equation
In general terms, an equation \(\frac{x^{2}}{a^{2}}-\frac{y^{2}}{b^{2}}=0\) is a hyperbola when \(a ≠ b\) and a pair of intersecting lines when \(a = b\).
Other exercises in this chapter
Problem 63
Describe how to locate the foci for \(\frac{x^{2}}{25}+\frac{y^{2}}{16}=1\).
View solution Problem 65
Describe one similarity and one difference between the graphs of \(\frac{x^{2}}{25}+\frac{y^{2}}{16}=1\) and \(\frac{(x-1)^{2}}{25}+\frac{(y-1)^{2}}{16}=1\).
View solution Problem 65
Use a graphing utility to graph the parabolas.Write the given equation as a quadratic equation in \(y\) and use the quadratic formula to solve for \(y .\) Enter
View solution Problem 66
Graph \(\frac{x^{2}}{a^{2}}-\frac{y^{2}}{b^{2}}=1\) and \(\frac{x^{2}}{a^{2}}-\frac{y^{2}}{b^{2}}=-1\) in the same viewing rectangle for values of \(a^{2}\) and
View solution