Problem 65
Question
True or False? In Exercises \(63-66,\) determine whether the statement is true or false. If it is false, explain why or give an example that shows it is false. If the interval of convergence for \(\sum_{n=0}^{\infty} a_{n} x^{n}\) is \((-1,1),\) then the interval of convergence for \(\sum_{n=0}^{\infty} a_{n}(x-1)^{n}\) is (0,2) .
Step-by-Step Solution
Verified Answer
True
1Step 1: Understand the Statement
In a power series \(\sum_{n=0}^{\infty} a_{n} x^{n}\), the interval of convergence is the set of x-values for which the series converges. If we replace \(x\) with \((x-1)\), it essentially shifts the interval of convergence to the right by 1 unit. This change doesn't widen or shorten the interval, simply shifts it.
2Step 2: Apply Shift to the Original Interval
The original interval of convergence is \((-1,1)\). If we shift this interval to the right by 1 unit, we get the interval \((0,2)\). This means we're replacing each x-value in the original interval with \((x-1)\), which results in the shifted interval.
3Step 3: Final Verification
Having shifted the interval appropriately, we see it matches the interval given in the statement, which is \((0,2)\). Therefore, the given statement is indeed true.
Key Concepts
Interval of ConvergenceConvergence of SeriesShifting Intervals
Interval of Convergence
The interval of convergence of a power series \(\sum_{n=0}^{\infty} a_{n} x^{n}\) is the set of all \(x\)-values for which the series converges. To understand this, think of it as finding the "safe zone" where the series behaves nicely, summing up to a finite number. This interval might have endpoints where the series converges or diverges. Thus, it's essential to test these endpoints to determine their status.
- This interval can be bounded, like \((-1, 1)\), meaning it covers all numbers between -1 and 1 but not the endpoints themselves.
- It is crucial to identify whether each endpoint is included (closed interval) or excluded (open interval), noted by brackets \([a, b]\) or parentheses \((a, b)\).
Convergence of Series
A series converges when the sum of its infinite terms results in a finite value. In the context of power series, such as \(\sum_{n=0}^{\infty} a_{n} x^{n}\), convergence means finding values of \(x\) that make the infinite sum reach a specific number, rather than running off to infinity.
- Convergence is closely related to the radius of convergence, which is the distance from the center of the series to the endpoints of the interval of convergence.
- The series converges absolutely if it converges for all points within a certain radius, and conditionally at the endpoints.
Shifting Intervals
Shifting intervals in the context of power series involves changing the variable to translate the interval of convergence. For example, in the series \(\sum_{n=0}^{\infty} a_{n}(x-1)^{n}\), replacing \(x\) with \((x-1)\) shifts all \(x\)-values in the interval to the right by 1 unit.
- In the given example, the original interval \((-1,1)\) becomes \((0,2)\) after shifting. This doesn't change the width of the interval (both are of length 2).
- Shifting is a straightforward process but requires careful adjustment of endpoints to ensure the new interval correctly reflects convergence limits.
Other exercises in this chapter
Problem 65
Determine the convergence or divergence of the series. $$ \sum_{n=1}^{\infty}\left(1+\frac{k}{n}\right)^{n} $$
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Determine whether the sequence with th given \(n\) th term is monotonic. Discuss the boundedness of th sequence. Use a graphing utility to confirm your results.
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A projectile fired from the ground follows the trajectory given by $$ y=\left(\tan \theta-\frac{g}{k v_{0} \cos \theta}\right) x-\frac{g}{k^{2}} \ln \left(1-\fr
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Use the Root Test to determine the convergence or divergence of the series. $$ \sum_{n=2}^{\infty} \frac{(-1)^{n}}{(\ln n)^{n}} $$
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