Problem 65
Question
The Ehrenberg relation $$ \ln W=\ln 2.4+(1.84) h $$ is an empirically based formula relating the height \(h\) (in meters) to the average weight \(W\) (in kilograms) for children 5 through 13 years old. (a) Express \(W\) as a function of \(h\) that does not contain \(\ln\). (b) Estimate the average weight of an 8-year-old child who is \(1.5\) meters tall.
Step-by-Step Solution
Verified Answer
The average weight of a 1.5 meter tall 8-year-old is approximately 37.85 kg.
1Step 1: Isolate W in the Equation
The given equation is \( \ln W = \ln 2.4 + 1.84h \). To express \( W \) as a function of \( h \), we need to get rid of the natural logarithm. We can do this by exponentiating both sides of the equation to solve for \( W \). This leads to \( W = e^{\ln 2.4 + 1.84h} \).
2Step 2: Simplify the Exponentiation
Using the properties of exponents: \( e^{a+b} = e^a \cdot e^b \), we rewrite the equation as \( W = e^{\ln 2.4} \cdot e^{1.84h} \). Since \( e^{\ln 2.4} = 2.4 \), the expression simplifies to \( W = 2.4 \cdot e^{1.84h} \). Thus, \( W(h) = 2.4 \cdot e^{1.84h} \).
3Step 3: Substitute h = 1.5 to Estimate W
Now we will estimate the average weight of an 8-year-old child who is 1.5 meters tall by substituting \( h = 1.5 \) into the function \( W(h) = 2.4 \cdot e^{1.84h} \). This gives us \( W(1.5) = 2.4 \cdot e^{1.84 \times 1.5} \).
4Step 4: Calculate the Exponential Term
Calculate \( 1.84 \times 1.5 = 2.76 \). Therefore, \( W(1.5) = 2.4 \cdot e^{2.76} \). Use a calculator to find \( e^{2.76} \).
5Step 5: Final Calculation and Result
Using a calculator, \( e^{2.76} \approx 15.77 \). Therefore, \( W = 2.4 \times 15.77 \approx 37.85 \). The estimated average weight of an 8-year-old child who is 1.5 meters tall is approximately 37.85 kilograms.
Key Concepts
ExponentiationNatural LogarithmFunction Notation
Exponentiation
Exponentiation is a mathematical operation that raises a number, known as the base, to the power of an exponent. In the Ehrenberg relation, exponentiation is crucial for transforming expressions involving logarithms. When working with the equation \( \ln W = \ln 2.4 + 1.84h \), exponentiating each side helps remove the natural logarithm, simplifying our work.
- Exponentiation essentially "undoes" logarithms. This principle transforms log equations into more manageable forms.
- The formula \( e^{a+b} = e^a \cdot e^b \) is an essential property that allows decomposition of exponents, as used in this problem.
- Knowing that \( e^{\ln x} = x \), helps simplify expressions by canceling the logarithm with the exponential function.
Natural Logarithm
The natural logarithm, denoted as \( \ln \), is a logarithm to the base \( e \), where \( e \approx 2.71828 \). It often arises in natural growth patterns and exponential decay.
- The natural logarithm allows for the expression of relationships, like those in the Ehrenberg relation, in a linear form before converting.
- Logarithms provide a powerful way to simplify multiplication into addition, which was the initial form of the relation: \( \ln W = \ln 2.4 + 1.84h \).
- In many scientific formulas, logarithms are used to linearize exponential dynamics, which makes them easier to manipulate mathematically.
Function Notation
Function notation is a method to denote a function's output concerning its input variables, often written as \( f(x) \) or in this case, \( W(h) \). It’s a concise way to represent the relationship between dependent and independent variables.
- Here, \( W(h) = 2.4 \cdot e^{1.84h} \) denotes the weight \( W \) as a function of height \( h \), clearly showing we derive \( W\) from \( h \).
- Function notation conveys the dependency and relationship inside our equation, making it explicitly clear what value depends on what variable.
- This notation is convenient for substituting numeric values to calculate specific results, such as predicting the weight for given heights, like the 1.5-meter child example.
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