Problem 65
Question
Test score distribution. In a large class, student test scores had a mean of \(\mu=76\) and a standard deviation \(\sigma=7\) a) The top \(12 \%\) of students got an \(A\). Find the minimum score needed to get an \(\mathrm{A}\) (round to the appropriate integer). b) The top \(75 \%\) of students passed. Find the minimum score needed to pass (round to the appropriate integer).
Step-by-Step Solution
Verified Answer
a) 84
b) 71
1Step 1: Define the Problem for Part (a)
We need to find the minimum score needed to get an A, given the top 12% of students received an A. This means we are looking at the cutoff score for the 88th percentile in a normal distribution with mean \(\mu=76\) and standard deviation \(\sigma=7\).
2Step 2: Find the Z-Score for the 88th Percentile
Using the Z-table or a standard normal distribution calculator, we find the Z-score that corresponds to the cumulative probability of 0.88. The Z-score for 0.88 is approximately 1.175.
3Step 3: Compute the Minimum Score Using the Z-Score
We use the Z-score formula to find the minimum score: \[ x = \mu + Z\cdot\sigma = 76 + 1.175\cdot7 \approx 84.225 \]Rounding this to the nearest whole number, the minimum score required to get an A is 84.
4Step 4: Define the Problem for Part (b)
For part b, we need to determine the minimum score needed to pass, which corresponds to the 25th percentile (since we want the top 75% of students).
5Step 5: Find the Z-Score for the 25th Percentile
Using the Z-table or a standard normal distribution calculator, we find the Z-score for a cumulative probability of 0.25. The Z-score for 0.25 is approximately -0.675.
6Step 6: Compute the Minimum Passing Score Using the Z-Score
Apply the Z-score formula to find the minimum score that constitutes the 25th percentile:\[ x = \mu + Z\cdot\sigma = 76 + (-0.675)\cdot7 \approx 71.275 \]Rounding this to the nearest whole number, the minimum passing score is 71.
Key Concepts
PercentilesZ-score calculationTest score analysis
Percentiles
Understanding percentiles is crucial when analyzing data, especially in a normal distribution. Percentiles indicate the relative standing of a value within a data set.
*They tell us how a particular score compares to the rest of the data.*
For instance, if a test score is in the 88th percentile, it means that the score is higher than 88% of the other scores in the distribution.
*They tell us how a particular score compares to the rest of the data.*
For instance, if a test score is in the 88th percentile, it means that the score is higher than 88% of the other scores in the distribution.
- The **88th percentile** implies that 12% of scores are above and 88% are below.
- The **25th percentile**, also known as the first quartile, means 25% of scores are below and 75% are above.
Z-score calculation
Calculating the Z-score is essential for finding where a specific score stands within the normal distribution. The Z-score represents the number of standard deviations a particular data point is from the mean.
*It's a tool used to convert test scores into a standard form that reveals comparative standings.*
*It's a tool used to convert test scores into a standard form that reveals comparative standings.*
- For finding the **88th percentile**, we determine a Z-score by setting the cumulative probability at 0.88.
- Conversely, for the **25th percentile**, a Z-score corresponds to a cumulative probability of 0.25.
Test score analysis
With test score analysis, the goal is to understand the distribution of scores and make decisions based on statistical measurements. *This involves applying percentiles and Z-scores to draw meaningful conclusions.*
- **Identifying top performers:** By analyzing the top 12% of scores, an educator can determine what scores qualify as an 'A'.
- **Evaluating pass/fail thresholds:** Calculating the cut-off for the 25th percentile allows educators to set a fair and consistent passing score.
Other exercises in this chapter
Problem 64
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