Problem 65
Question
Solve each nonlinear system of equations analytically for all real solutions. $$\begin{aligned} x^{2}+y^{2} &=10 \\ 2 x^{2}-y^{2} &=17 \end{aligned}$$
Step-by-Step Solution
Verified Answer
The real solutions are \((3, 1)\), \((3, -1)\), \((-3, 1)\), and \((-3, -1)\).
1Step 1: Identify the System
We are given two equations: 1. \( x^2 + y^2 = 10 \) 2. \( 2x^2 - y^2 = 17 \). We need to solve these equations simultaneously to find all real solutions for \(x\) and \(y\).
2Step 2: Express One Equation in Terms of Another
From the first equation, \( x^2 + y^2 = 10 \), isolate \( y^2 \) to obtain:\[ y^2 = 10 - x^2. \]
3Step 3: Substitute to Solve for One Variable
Substitute \( y^2 = 10 - x^2 \) from Step 2 into the second equation: \[ 2x^2 - (10 - x^2) = 17. \]Simplify the equation to:\[ 2x^2 - 10 + x^2 = 17. \]Combine terms to get:\[ 3x^2 - 10 = 17. \]
4Step 4: Solve for \(x^2\)
Add 10 to both sides to give:\[ 3x^2 = 27 \]Divide both sides by 3:\[ x^2 = 9. \]
5Step 5: Solve for \(x\)
Take the square root of both sides to find \(x\):\[ x = 3 \quad \text{or} \quad x = -3. \]
6Step 6: Substitute Back to Find \(y\)
Substitute \( x = 3 \) and \( x = -3 \) back into the equation \( y^2 = 10 - x^2 \).For \( x = 3 \): \[ y^2 = 10 - 9 \quad \Rightarrow \quad y^2 = 1 \quad \Rightarrow \quad y = 1 \quad \text{or} \quad y = -1. \]For \( x = -3 \): The same operation gives:\[ y^2 = 10 - 9 \quad \Rightarrow \quad y^2 = 1 \quad \Rightarrow \quad y = 1 \quad \text{or} \quad y = -1. \]
7Step 7: List All Solutions
We combine the \( x \) and \( y \) values to give the solutions for the system: 1. \( (3, 1) \) 2. \( (3, -1) \) 3. \( (-3, 1) \) 4. \( (-3, -1) \).
Key Concepts
Analytical SolutionQuadratic EquationsSimultaneous Equations
Analytical Solution
An analytical solution refers to a way of solving mathematical problems using algebraic expressions and known formulas, rather than numerical or graphical means. In solving nonlinear systems of equations, like the example provided, the main goal is to find exact values for the variables.
The steps employed involved:
The steps employed involved:
- Identifying the equations as a system, noting that each equation contains the same set of variables.
- Using algebraic methods to manipulate the equations, such as substitution or elimination, to express one variable in terms of another.
- Simplifying to solve for each variable individually, ensuring all possible solutions are accounted for.
Quadratic Equations
Quadratic equations are polynomial equations of degree two, and they appear frequently in algebra. In the context of the given exercise, the equations involve terms like \( x^2 \) and \( y^2 \), which are characteristic of quadratics.
A basic quadratic equation looks like \( ax^2 + bx + c = 0 \). Here, 'a', 'b', and 'c' are constants. Solving these equations typically involves:
A basic quadratic equation looks like \( ax^2 + bx + c = 0 \). Here, 'a', 'b', and 'c' are constants. Solving these equations typically involves:
- Factoring the polynomial expression, if possible.
- Using the quadratic formula \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \) to find solutions when the quadratic cannot be factored easily.
- Completing the square, another method less often used but effective in certain conditions.
Simultaneous Equations
Simultaneous equations are a set of equations with multiple variables, often requiring a solution for all variables involved at the same time. These can be linear or nonlinear based on the degree of the equations.
When dealing with nonlinear systems, like in our exercise, where one equation is quadratic, we often use methods such as:
When dealing with nonlinear systems, like in our exercise, where one equation is quadratic, we often use methods such as:
- Substitution, as shown in the steps, where you solve one equation for a variable and substitute into another.
- Elimination, which involves adding or subtracting equations to eliminate a variable.
- Graphical methods, though less precise, involve plotting each equation to find points of intersection, giving a visual solution.
Other exercises in this chapter
Problem 65
Find an equation for each hyperbola. Asymptotes \(y=\pm \frac{3}{5} x ; y\) -intercepts \((0, \pm 3)\)
View solution Problem 65
For the graph of \((x-h)^{2}=4 c(y-k)\), in what quadrant is the vertex for each condition? (a) \(h0\) (c) \(h>0, k0, k>0\)
View solution Problem 66
Find an equation for each hyperbola. \(y\) -intercept \((0,-2)\); center at origin; passing through \((2,3)\)
View solution Problem 66
Solve each nonlinear system of equations analytically for all real solutions. $$\begin{aligned} x^{2}+y^{2} &=4 \\ 2 x^{2}-3 y^{2} &=-12 \end{aligned}$$
View solution