Problem 65
Question
Solve each compound inequality, if possible. Graph the solution set (if one exists) and write it using interval notation. \(-24<\frac{3}{2} x-6 \leq-15\)
Step-by-Step Solution
Verified Answer
Solution in interval notation:
\((-12, -6]\)
1Step 1: Understand the Compound Inequality
The given inequality is a compound inequality, which means we have two inequalities combined. It can be written as \(-24 < \frac{3}{2}x - 6\) and \(\frac{3}{2}x - 6 \leq -15\). We need to solve these two inequalities separately and then find the intersection of their solution sets.
2Step 2: Solve the Left Inequality
Start with the inequality \(-24 < \frac{3}{2}x - 6\).First, add 6 to both sides to isolate the term with \(x\):\[-24 + 6 < \frac{3}{2}x \Rightarrow -18 < \frac{3}{2}x\]Next, multiply both sides by the reciprocal of \(\frac{3}{2}\), which is \(\frac{2}{3}\), to solve for \(x\):\[-18 \times \frac{2}{3} < x \Rightarrow x > -12\].
3Step 3: Solve the Right Inequality
Now solve \(\frac{3}{2}x - 6 \leq -15\).First, add 6 to both sides:\[\frac{3}{2}x - 6 + 6 \leq -15 + 6 \Rightarrow \frac{3}{2}x \leq -9\]Next, multiply both sides by \(\frac{2}{3}\) to solve for \(x\):\[x \leq -9 \times \frac{2}{3} \Rightarrow x \leq -6\].
4Step 4: Combine the Solutions
Combine the solutions from Step 2 and Step 3. We have:\(x > -12\) from Step 2 and \(x \leq -6\) from Step 3. To find the compound solution, take the intersection of these two:\(-12 < x \leq -6\).
5Step 5: Write the Solution in Interval Notation
Express the solution \(-12 < x \leq -6\) in interval notation. This corresponds to:\((-12, -6]\).
6Step 6: Graph the Solution
The graph of the solution \((-12, -6]\) is a number line:- Draw an open circle at \(-12\), indicating \(x\) cannot equal \(-12\).- Draw a closed circle at \(-6\), showing \(x\) can equal \(-6\).- Shade the region between these two points to represent all possible values of \(x\).
Key Concepts
Interval NotationSolving InequalitiesNumber Line Graphing
Interval Notation
Interval notation is a way of writing the solution set of inequalities. It helps to succinctly express a range of values that a variable can take. When solving compound inequalities, interval notation allows you to represent the solution in a compact form.
In interval notation, brackets—or parentheses—are used to describe the set:
In interval notation, brackets—or parentheses—are used to describe the set:
- Round brackets, \(( \text{ and } )\), indicate that the number next to it is not included in the set. This is often used with open inequalities like \(x > -12\).
- Square brackets, \([ \text{ and } ]\), show that the number is included. This is used with closed inequalities like \(x \leq -6\).
Solving Inequalities
Solving inequalities involves finding the set of values that satisfy the given inequalities. It resembles solving equations but with additional rules for applications such as multiplying or dividing by negative numbers.
For our compound inequality \(-24 < \frac{3}{2}x - 6 \leq -15\), we isolated terms involving \(x\) in two separate parts. The process includes:
For our compound inequality \(-24 < \frac{3}{2}x - 6 \leq -15\), we isolated terms involving \(x\) in two separate parts. The process includes:
- Adding or subtracting terms to both sides to simplify the inequality expression.
- Multiplying or dividing the entire inequality by a positive number, maintaining the inequality's direction. If it's by a negative number, reverse the inequality sign.
Number Line Graphing
Graphing solutions on a number line provides a visual representation of an inequality solution, making it easier to understand how solutions are spread across numbers.
Once you determine the solution to a compound inequality, like \((-12, -6]\), graphing involves:
Once you determine the solution to a compound inequality, like \((-12, -6]\), graphing involves:
- Drawing a line to represent all real numbers.
- Using open circles to indicate numbers that are not part of the solution set (\(x\) does not include \(-12\)).
- Using closed circles to show numbers that are in the solution set (\(x\) does include \(-6\)).
- Shading the segment between these points to illustrate the complete solution range.
Other exercises in this chapter
Problem 64
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