Problem 65
Question
Solve each absolute value equation or indicate the equation has no solution. $$ 2|3 x-2|=14 $$
Step-by-Step Solution
Verified Answer
The solutions are \(x = 3\) and \(x = -5/3\).
1Step 1: Interpret absolute value
An absolute value equation can be translated into two separate equations. So, here it will branch into: \(3x - 2 = 7\) and \(3x - 2 = -7\)
2Step 2: Solve the first equation
Let's solve the first equation; \(3x - 2 = 7\). Adding 2 to both sides, we get \(3x = 9\). Dividing each side by 3, we get \(x = 3\).
3Step 3: Solve the second equation
Now, solve the second equation; \(3x - 2 = -7\). Adding 2 to both sides, we get \(3x = -5\). Dividing each side by 3, we get \(x = -5/3\) or -1.67 to two decimal places.
Key Concepts
Solving Absolute Value EquationsEquation TransformationIsolation of VariablesAlgebraic Solutions
Solving Absolute Value Equations
In mathematics, absolute values represent the distance a number is from zero on a number line. When tackling absolute value equations, such as \(2|3x-2|=14\), understanding this concept is crucial. The absolute value of an expression affects how equations are set up and solved.
Absolute value equations are solved by splitting the equation into two possible cases. This step arises from the definition of absolute value, which states that \(|a| = a\) if \(a \geq 0\) or \(|a| = -a\) if \(a < 0\). Consequently, the equation \(2|3x-2|=14\) transforms into two potential scenarios to solve:
Recognizing the dual scenarios is a key step in accurately solving absolute value equations.
Absolute value equations are solved by splitting the equation into two possible cases. This step arises from the definition of absolute value, which states that \(|a| = a\) if \(a \geq 0\) or \(|a| = -a\) if \(a < 0\). Consequently, the equation \(2|3x-2|=14\) transforms into two potential scenarios to solve:
- \(3x - 2 = 7\)
- \(3x - 2 = -7\)
Recognizing the dual scenarios is a key step in accurately solving absolute value equations.
Equation Transformation
Equation transformation is a fundamental process in mathematics, allowing equations to be rewritten in simpler or alternative forms. With absolute value equations, transformation involves setting up equivalent equations to eliminate the absolute value.
In our example, the starting equation is \(2|3x-2|=14\). The first transformation step is to divide both sides by 2 to isolate the absolute value alone:
In our example, the starting equation is \(2|3x-2|=14\). The first transformation step is to divide both sides by 2 to isolate the absolute value alone:
- \(|3x - 2| = 7\)
- \(3x - 2 = 7\)
- \(3x - 2 = -7\)
Isolation of Variables
Isolation of variables is an essential algebra technique used to solve for unknowns. When dealing with linear equations, the goal is to manipulate the equation so that the unknown variable stands alone on one side of the equation. This process uncovers the solution by making the variable's value explicit.
In the absolute value equation \(3x - 2 = 7\), the first step is to eliminate constants from the side with the variable. We add 2 to both sides to achieve this:
In the absolute value equation \(3x - 2 = 7\), the first step is to eliminate constants from the side with the variable. We add 2 to both sides to achieve this:
- \(3x - 2 + 2 = 7 + 2 \rightarrow 3x = 9\)
- \(x = 3\)
- \(3x = -5 \rightarrow x = -5/3\)
Algebraic Solutions
The final step in solving equations typically involves obtaining algebraic solutions where the variable of interest is isolated, providing direct answers to the problem.
When simplified, each algebraic equation yields solutions indicating the values for \(x\) that satisfy the original equation. For the first equation, \(3x = 9\), solving gives \(x = 3\). This becomes one valid solution because it maintains the original equation's integrity.
For the second equation, \(3x = -5\), solving offers \(x = -\frac{5}{3}\), another viable solution. Each algebraic solution reflects a possible value the variable may assume to equate both sides of the original absolute value condition.
When assessing absolute value equations, always verify these solutions in the context of the problem to ensure they satisfy the initial constraints. This verification process helps determine the feasibility of the proposed solutions.
When simplified, each algebraic equation yields solutions indicating the values for \(x\) that satisfy the original equation. For the first equation, \(3x = 9\), solving gives \(x = 3\). This becomes one valid solution because it maintains the original equation's integrity.
For the second equation, \(3x = -5\), solving offers \(x = -\frac{5}{3}\), another viable solution. Each algebraic solution reflects a possible value the variable may assume to equate both sides of the original absolute value condition.
When assessing absolute value equations, always verify these solutions in the context of the problem to ensure they satisfy the initial constraints. This verification process helps determine the feasibility of the proposed solutions.
Other exercises in this chapter
Problem 64
The equations in Exercises \(59-70\) combine the types of equations we have discussed in this section. Solve each equation or state that it is true for all real
View solution Problem 65
Compute the discriminant of each equation in Exercises 65-72 What does the discriminant indicate about the number and type of solutions? \(x^{2}-4 x-5=0\)
View solution Problem 65
In Exercises \(57-76,\) solve each formula for the specified variable. Do you recognize the formula? If so, what does it describe? \(T=D+p m\) for \(p\)
View solution Problem 65
Solve each inequality in Exercises 57-84 by first rewriting each one as an equivalent inequality without absolute value bars. Graph the solution set on a number
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