Problem 65
Question
In Problems \(63-66\), convert the points given in rectangular coordinates to spherical coordinates. $$ \left(\frac{\sqrt{3}}{2}, \frac{1}{2}, 1\right) $$
Step-by-Step Solution
Verified Answer
The spherical coordinates are \(\left(\sqrt{2}, \frac{\pi}{6}, \frac{\pi}{4}\right)\).
1Step 1: Understand Rectangular to Spherical Conversion
To convert from rectangular coordinates \(x, y, z\) to spherical coordinates \(\rho, \theta, \phi\), use the following formulas: \(\rho = \sqrt{x^2 + y^2 + z^2}\), \(\theta = \tan^{-1}(\frac{y}{x})\), and \(\phi = \cos^{-1}(\frac{z}{\rho})\).
2Step 2: Calculate \(\rho\) (The Radius)
First, calculate the radius \(\rho\) using the formula \(\rho = \sqrt{x^2 + y^2 + z^2}\). Substitute the given values for x, y, and z:\(\rho = \sqrt{\left(\frac{\sqrt{3}}{2}\right)^2 + \left(\frac{1}{2}\right)^2 + (1)^2} = \sqrt{\frac{3}{4} + \frac{1}{4} + 1} = \sqrt{2}\)
3Step 3: Calculate \(\theta\) (The Azimuthal Angle)
Next, calculate the angle \(\theta\) using the formula \(\theta = \tan^{-1}\left(\frac{y}{x}\right)\). Substitute the values of x and y:\(\theta = \tan^{-1}\left(\frac{\frac{1}{2}}{\frac{\sqrt{3}}{2}}\right) = \tan^{-1}\left(\frac{1}{\sqrt{3}}\right) = \frac{\pi}{6}\)
4Step 4: Calculate \(\phi\) (The Polar Angle)
Finally, compute the angle \(\phi\) using the formula \(\phi = \cos^{-1}(\frac{z}{\rho})\). Using the calculated radius and given value for z:\(\phi = \cos^{-1}\left(\frac{1}{\sqrt{2}}\right) = \frac{\pi}{4}\)
5Step 5: Final Result: Combine Spherical Coordinates
Combine the calculated components to find the spherical coordinates: \(\left(\rho, \theta, \phi\right) = \left(\sqrt{2}, \frac{\pi}{6}, \frac{\pi}{4}\right)\).
Key Concepts
Rectangular CoordinatesCoordinate TransformationTrigonometric Functions
Rectangular Coordinates
Rectangular coordinates are one of the most common coordinate systems used in mathematics and physics. In this system, any point in space is described by three values:
- **X-coordinate**: Measures the point's horizontal distance in the x-direction.
- **Y-coordinate**: Represents the vertical position along the y-direction.
- **Z-coordinate**: Indicates how high or low the point is along the z-axis.
Coordinate Transformation
Coordinate transformation is the process of converting points from one coordinate system to another, such as from rectangular to spherical coordinates. Such transformations are vital for solving problems where one system of coordinates is more convenient than another. For conversions like arithmetic and trigonometric calculations, spherical coordinates often make 3D problems simpler. The formulas used in transforming from rectangular \((x,y,z)\) to spherical coordinates \((\rho, \theta, \phi)\) are:
- **\(\rho\)**: The radial distance. Calculate by \(\rho = \sqrt{x^2 + y^2 + z^2}\), indicating the point's distance from the origin.
- **\(\theta\)**: The azimuthal angle (in the x-y plane), found using \(\theta = \tan^{-1}\left(\frac{y}{x}\right)\).
- **\(\phi\)**: The polar angle (angle from the z-axis), calculated through \(\phi = \cos^{-1}\left(\frac{z}{\rho}\right)\).
Trigonometric Functions
Trigonometric functions play a crucial role in converting between various coordinate systems, notably between rectangular and spherical coordinates. They help us understand angles and distances between points relative to specific axes. In the process of coordinate transformation, two trigonometric functions are essential:
- **Tangent Function**: Used to find the angle \(\theta\) in the x-y plane. This helps determine the direction of the point from the origin.
- **Inverse Tangent**: Calculated by its formula \(\tan^{-1}\left(\frac{y}{x}\right)\), gives the azimuthal angle \(\theta\), providing insight into the radial alignment in horizontal planes.
- **Cosine Function**: Applied to find the angle \(\phi\). It measures the deviation from the z-axis and is calculated using \(\cos^{-1}\left(\frac{z}{\rho}\right)\).
Other exercises in this chapter
Problem 64
In Problems \(63-66\), convert the points given in rectangular coordinates to spherical coordinates. $$ (1,-\sqrt{3}, 1) $$
View solution Problem 64
Convert the points given in rectangular coordinates to spherical coordinates. $$ (1,-\sqrt{3}, 1) $$
View solution Problem 65
Find the polar moment of inertia of the lamina that has the given shape and density. \(x=y^{2}+2, x=6-y^{2}\); density at a point \(P\) inversely proportional t
View solution Problem 65
Convert the points given in rectangular coordinates to spherical coordinates. $$ \left(\frac{\sqrt{3}}{2}, \frac{1}{2}, 1\right) $$
View solution