Problem 65
Question
In Exercises \(63-66\), solve the equation. $$ z^{2}-4 z-12=0 $$
Step-by-Step Solution
Verified Answer
The solutions to the equation \(z^{2}-4z-12=0\) are \(z = 6\) and \(z = -2\).
1Step 1: Identify a, b, and c
From the given quadratic equation \(z^{2} - 4z -12 = 0\), identify \(a = 1\), \(b = -4\), and \(c = -12\).
2Step 2: Calculate Discrepant (\(b^2-4ac\))
Before we can use the quadratic formula, we need to calculate the value of the discrepant: \(b^{2} - 4ac = (-4)^{2} - 4(1)(-12) = 16 + 48 = 64\).
3Step 3: Substitute a, b, and c into the Quadratic Formula
Substitute \(a=1\), \(b=-4\), and \(c=-12\) into the quadratic formula to find the roots: \(z = \frac{-(-4) \pm \sqrt{64}}{2(1)} = \frac{4 \pm 8}{2}\).
4Step 4: Solve for z
We get two solutions for z, \(z = \frac{4 + 8}{2} = 6\) and \(z = \frac{4 - 8}{2} = -2\) are the roots of the given quadratic equation.
Key Concepts
Quadratic FormulaDiscriminantRoots of a Polynomial
Quadratic Formula
The quadratic formula is an essential tool for solving quadratic equations of the form \( ax^2 + bx + c = 0 \). This formula allows us to find the roots of any quadratic equation by simply plugging in the values of \( a \), \( b \), and \( c \).
The formula itself is expressed as:
Remember that \( a \), \( b \), and \( c \) are the numerical coefficients in your quadratic equation. Once these are identified, you can direct your attention to calculating the discriminant to proceed further using the formula.
The formula itself is expressed as:
- \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \)
Remember that \( a \), \( b \), and \( c \) are the numerical coefficients in your quadratic equation. Once these are identified, you can direct your attention to calculating the discriminant to proceed further using the formula.
Discriminant
The discriminant is a critical part of the quadratic formula, as it determines the nature of the roots. Found under the square root in the quadratic formula, it is represented as:
- \( b^2 - 4ac \)
- If \( b^2 - 4ac = 0 \), there is exactly one real root.
- If \( b^2 - 4ac > 0 \), there are two distinct real roots.
- If \( b^2 - 4ac < 0 \), the equation has two complex roots.
Roots of a Polynomial
In solving quadratic equations, finding the roots is essentially finding the values of \( z \) (or \( x \), etc.) that satisfy the equation \( ax^2 + bx + c = 0 \). These roots are also known as the solutions of the polynomial. Essentially, they are the values where the polynomial equals zero.
Using the quadratic formula, we derived two roots for the equation \( z^{2} - 4z - 12 = 0 \):
The concept of roots is vital because it tells you about the behavior of the polynomial and its graphical representation. Comprehending this connection aids in understanding how changes to the polynomial's coefficients alter its shape and position on the graph.
Using the quadratic formula, we derived two roots for the equation \( z^{2} - 4z - 12 = 0 \):
- \( z = 6 \)
- \( z = -2 \)
The concept of roots is vital because it tells you about the behavior of the polynomial and its graphical representation. Comprehending this connection aids in understanding how changes to the polynomial's coefficients alter its shape and position on the graph.
Other exercises in this chapter
Problem 64
In Exercises 61-64, solve the equation and check your solution. $$ y+6(3-2 y)=4 $$
View solution Problem 65
In Exercises \(63-66\), sketch the graph of the equation. $$ 0.3 x-0.2 y=0.8 $$
View solution Problem 65
In Exercises 65-68, solve the rational equation. $$ \frac{x}{5}+\frac{2 x}{5}=3 $$
View solution Problem 66
In Exercises \(63-66\), sketch the graph of the equation. $$ x=6 $$
View solution