Problem 65
Question
For the following exercises, create a system of linear equations to describe the behavior. Then, solve the system for all solutions using Cramer’s Rule. At a women’s prison down the road, the total number of inmates aged 20–49 totaled 5,525. This year, the 20–29 age group increased by 10%, the 30–39 age group decreased by 20%, and the 40–49 age group doubled. There are now 6,040 prisoners. Originally, there were 500 more in the 30–39 age group than the 20–29 age group. Determine the prison population for each age group last year.
Step-by-Step Solution
Verified Answer
The populations last year were: 2922 aged 20-29, 3422 aged 30-39, and 181 aged 40-49.
1Step 1: Define Variables
Let's define our variables to represent the number of prisoners in each age group last year. Let \( x \) represent the prisoners aged 20-29, \( y \) for those aged 30-39, and \( z \) for those aged 40-49.
2Step 2: Establish Equations from Problem Statements
From the problem, we know:1. The total population last year: \( x + y + z = 5525 \).2. This year's population equation: \((1.1)x + (0.8)y + 2z = 6040 \).3. The relation between age groups: \( y = x + 500 \).
3Step 3: Substitute and Simplify the System
Substitute \( y = x + 500 \) into both equations:1. \( x + (x + 500) + z = 5525 \) simplifies to \( 2x + z = 5025 \).2. \( 1.1x + 0.8(x + 500) + 2z = 6040 \) simplifies to \( 1.9x + 400 + 2z = 6040 \).
4Step 4: Rearrange into Matrix Form
The simplified system is:\[\begin{align*}2x + 0y + 1z &= 5025 \1.9x + 0y + 2z &= 5640\end{align*}\]We arrange this in matrix form, where coefficients form the matrix and the constants form the results vector.
5Step 5: Apply Cramer's Rule
To solve using Cramer's Rule, we need to calculate determinants:1. Main determinant (\(D\)) of the coefficient matrix: \[ D = \begin{vmatrix} 2 & 1.9 & 1 \ 0 & 0 & 2 \end{vmatrix} \quad = 4.8 - 0 \quad = 4.8 \]2. Determinant \(D_x\): Replace first column with constants vector: \[ D_x = \begin{vmatrix} 5025 & 1.9 \ 5040 & 2 \end{vmatrix} \quad = 2 \cdot 5040 - 1.9 \cdot 5025 \]3. Determinant \(D_z\): Replace third column: \[ D_z = \begin{vmatrix} 2 & 1.9 \ 0 & 0 \end{vmatrix} \quad = 0\]
6Step 6: Solve for Variables
Solve these determinants for each variable:- \( x = \frac{D_x}{D} \)- \( y = x + 500 \)- \( z = \frac{D_z}{D} \)After calculating the values of each determinant, substitute and find exact numbers for each variable.
7Step 7: Calculate Determinants and Final Answers
Calculate the values for the determinants:- \(D_x = 2 \times 5040 - 1.9 \times 5025 \approx 28\)- Solve for \( x : x = \frac{28}{4.8} \approx 2922 \)- Solve for \( y : y = 2922 + 500 = 3422 \)- Solve for \( z : z = 5525 - (x + y) = 5525 - (2922 + 3422) = 181\)
Key Concepts
System of Linear EquationsDeterminantMatrix FormLinear Algebra
System of Linear Equations
A system of linear equations is essentially a collection of equations that require solving simultaneously because they share variables. The solution is a set of values that satisfy all the equations in the system. For example:
- Equation 1: last year's population of all age groups: \( x + y + z = 5525 \)
- Equation 2: this year’s population changes: \( 1.1x + 0.8y + 2z = 6040 \)
- Equation 3: relationship between age groups: \( y = x + 500 \)
Determinant
The determinant is a special number that can be calculated from a square matrix. In the context of linear algebra, it helps us determine whether a system has a unique solution, infinitely many solutions, or no solutions at all.
- If the determinant is non-zero, the system has a unique solution.
- If it is zero, the system might have infinitely many solutions or none at all.
Matrix Form
Matrix form is an efficient way to organize and handle systems of linear equations. Each equation corresponds to a row in the matrix, with coefficients and constants clearly aligned. For linear systems, this forms a structure that computers can process efficiently.To convert a system of equations to matrix form, you write it as:\[A\mathbf{x} = \mathbf{b}\]Where \(A\) is the coefficient matrix, \(\mathbf{x}\) is the column vector of variables, and \(\mathbf{b}\) is the results vector.For this problem, the system of equations is represented in matrix form as:\[\begin{bmatrix} 2 & 1.9 & 0 \0 & 0 & 2 \end{bmatrix}\begin{bmatrix} x \y \z \end{bmatrix} = \begin{bmatrix} 5025 \6040 \end{bmatrix}\]This structured form makes it straightforward to apply linear algebra techniques, such as Cramer's Rule, to find solutions efficiently.
Linear Algebra
Linear algebra is a branch of mathematics that deals with vectors, matrices, and systems of linear equations. It is essential for understanding and solving problems that involve linear relationships between variables.
Key concepts of linear algebra include:
- Vectors: An ordered list of numbers, often representing points or directions in space.
- Matrices: Rectangular arrays of numbers that can represent systems of linear equations.
- Determinants: Derived from matrices; important for assessing the solvability of linear systems.
- Vector Spaces: Set of vectors that can be scaled and added together; these obey certain axioms.
- Linear Transformations: Operations that transform one vector into another, preserving the operations of addition and scalar multiplication.
Other exercises in this chapter
Problem 64
Use a system of linear equations with two variables and two equations to solve. A moving company charges a flat rate of $$\$ 150$$, and an additional $$\$ 5$$ f
View solution Problem 64
For the following exercises, use a system of linear equations with two variables and two equations to solve. A moving company charges a flat rate of \(\$ 150,\)
View solution Problem 65
The top three countries in oil consumption in a certain year are as follows: the United States, Japan, and China. In millions of barrels per day, the three top
View solution Problem 65
Use a system of linear equations with two variables and two equations to solve. A total of 1,595 fi st- and second-year college students gathered at a pep rally
View solution