Problem 65
Question
For a lens combination, show that the total magnification \(M_{\text {total }}=M_{1} M_{2}\). [Hint: Think about the definition of magnification.
Step-by-Step Solution
Verified Answer
The total magnification is the product of the individual magnifications: \( M_{\text{total}} = M_1 M_2 \).
1Step 1: Understand Magnification
The magnification of a single lens, \( M \), is defined as the ratio of the height of the image \( h_i \) to the height of the object \( h_o \), which can also be expressed in terms of the object distance \( d_o \) and the image distance \( d_i \): \( M = \frac{h_i}{h_o} = \frac{d_i}{d_o} \).
2Step 2: Apply Magnification to the First Lens
For the first lens, consider the magnification \( M_1 \) which relates the image height after the first lens to the object height: \( M_1 = \frac{h_{i1}}{h_o} = \frac{d_{i1}}{d_{o1}} \). Here, \( h_{i1} \) is the height of the image formed by the first lens.
3Step 3: Use the Image as an Object for the Second Lens
The image formed by the first lens becomes the object for the second lens. Hence, the object height for the second lens is \( h_{i1} \). The magnification of the second lens is \( M_2 = \frac{h_{i2}}{h_{i1}} = \frac{d_{i2}}{d_{o2}} \).
4Step 4: Derive Total Magnification
The total magnification is the product of the magnifications of each lens. Calculate \( M_{\text{total}} = M_1 \times M_2 = \left(\frac{h_{i1}}{h_o}\right) \times \left(\frac{h_{i2}}{h_{i1}}\right) \). Simplifying this gives, \( M_{\text{total}} = \frac{h_{i2}}{h_o} \).
5Step 5: Conclude the Total Magnification Formula
Because the intermediate image height cancels out, the total magnification of the lens system is \( M_{\text{total}} = M_1 \times M_2 = \frac{h_{i2}}{h_o} \). This shows that the total magnification is indeed the product of the individual magnifications of the lenses.
Key Concepts
Lens CombinationImage DistanceObject Distance
Lens Combination
In optics, a lens combination refers to the use of two or more lenses in sequence to achieve a desired magnification or focus.
By examining a pair of lenses, we can understand how they collectively modify the path of light to form images. When light passes through the first lens, it forms an image. This image then acts as the object source for the second lens.
By examining a pair of lenses, we can understand how they collectively modify the path of light to form images. When light passes through the first lens, it forms an image. This image then acts as the object source for the second lens.
- The behavior of light through multiple lenses can change depending on the focal lengths and the arrangement.
- Each lens contributes based on its own properties, like refractive index and curvature.
Image Distance
Image distance refers to the distance from the lens to the point where the image is formed. This is typically denoted as \( d_i \) in lenses problems.
It plays a crucial role in determining the clarity and size of the image formed by a lens or lens system.
\[ \frac{1}{f} = \frac{1}{d_o} + \frac{1}{d_i} \]
Here, \( f \) is the focal length, \( d_o \) is the object distance, and \( d_i \) is the image distance. This formula helps in deciphering complex lens systems and their optical behavior.
It plays a crucial role in determining the clarity and size of the image formed by a lens or lens system.
- When using a single lens, the image distance depends on both the focal length of the lens and the object's distance from the lens.
- In a lens combination, the first lens creates an image that becomes the object for the second lens, altering the second lens's image distance.
\[ \frac{1}{f} = \frac{1}{d_o} + \frac{1}{d_i} \]
Here, \( f \) is the focal length, \( d_o \) is the object distance, and \( d_i \) is the image distance. This formula helps in deciphering complex lens systems and their optical behavior.
Object Distance
Object distance is the measure from the object to the lens, denoted as \( d_o \). Understanding object distance is fundamental to calculating the behavior of a lens, as it collaborates with focal length to determine where the image forms.
\[ \frac{1}{f} = \frac{1}{d_o} + \frac{1}{d_i} \]
This formula is the bedrock upon which lens equations are built, aiding in systematically exploring objects and their corresponding images in optical systems.
- Closer objects (small \( d_o \)) result in a larger, magnified image by the lens.
- When an image formed by the first lens acts as the 'object' for the second lens, we refer to the distance from this intermediate image to the second lens as the new \( d_o \).
\[ \frac{1}{f} = \frac{1}{d_o} + \frac{1}{d_i} \]
This formula is the bedrock upon which lens equations are built, aiding in systematically exploring objects and their corresponding images in optical systems.
Other exercises in this chapter
Problem 62
The human eye is a complex multiple-lens system. However, it can be approximated to an equivalent single converging lens with an average focal length about \(1.
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Two converging lenses \(L_{1}\) and \(L_{2}\) have focal lengths of \(30 \mathrm{~cm}\) and \(20 \mathrm{~cm}\), respectively. The lenses are placed \(60 \mathr
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Show that for thin lenses that have focal lengths \(f_{1}\) and \(f_{2}\) and are in contact, the effective focal length \((f)\) is given by $$ \frac{1}{f}=\fra
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An optometrist prescribes glasses with a power of \(-4.0 \mathrm{D}\) for a nearsighted student. What is the focal length of the glass lenses?
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