Problem 65
Question
Find the indicated \(n\) th partial sum of the arithmetic sequence. $$8,20,32,44, \ldots ; n=10$$
Step-by-Step Solution
Verified Answer
The 10th partial sum of the given arithmetic sequence is 620.
1Step 1: Identify the first term, the number of terms, and the common difference
The first term \(a\) in the arithmetic sequence is 8. The number of terms \(n\) to consider for the partial sum is given as 10. The common difference \(d\) can be determined by subtracting any term from the term that follows it, which is 12 in this case.
2Step 2: Calculate the last term
The last term \(l\) of the first 10 terms in the sequence can be found using the formula \(l = a + (n-1)d\). Substituting the values, we get: \(l = 8 + (10 - 1)12 = 116\)
3Step 3: Calculate the 10th partial sum
Use the formula for the \(n\)th partial sum of an arithmetic sequence, \(S_n = n/2 * (a + l)\). Substitute in the values we know: \(S_{10} = 10/2 * (8 + 116) = 5 * 124 = 620.
Key Concepts
Partial SumCommon DifferenceFirst Term
Partial Sum
In an arithmetic sequence, the partial sum refers to the sum of a certain number of terms from the start of the sequence up to a specified point. It is essentially the sum of the first few numbers that define the sequence.
For arithmetic sequences, there is a simple formula to find the partial sum: \[ S_n = \frac{n}{2}(a + l) \]where:
For arithmetic sequences, there is a simple formula to find the partial sum: \[ S_n = \frac{n}{2}(a + l) \]where:
- \( S_n \) is the partial sum
- \( n \) is the number of terms
- \( a \) is the first term
- \( l \) is the last term
Common Difference
The common difference in an arithmetic sequence is the consistent difference between consecutive terms. It is what makes the sequence "arithmetic," meaning that each term increases or decreases by the same amount from the previous term.
You can find the common difference by subtracting any term from the term that immediately follows it. For example, with the sequence 8, 20, 32, 44, ..., the common difference \( d \) is determined by: \[ d = 20 - 8 = 12 \]The common difference of 12 tells us that each term is 12 more than the term before it.
Understanding this concept is crucial because it allows us to predict future terms in the sequence and is also necessary for calculating the partial sum.
You can find the common difference by subtracting any term from the term that immediately follows it. For example, with the sequence 8, 20, 32, 44, ..., the common difference \( d \) is determined by: \[ d = 20 - 8 = 12 \]The common difference of 12 tells us that each term is 12 more than the term before it.
Understanding this concept is crucial because it allows us to predict future terms in the sequence and is also necessary for calculating the partial sum.
First Term
The first term in an arithmetic sequence is the starting point of the sequence—the very first number from which all other terms are derived. It is crucial because it anchors the entire sequence and is a key component of the formula used to find other aspects of the sequence, such as its partial sum.
In our example with the sequence 8, 20, 32, 44, ..., the first term \( a \) is 8. This initial value is important because it combines with the common difference to define the shape and direction of the entire sequence.
Often, knowing the first term allows you to find any other specific term or even the entire sequence, provided you also know the common difference.
In our example with the sequence 8, 20, 32, 44, ..., the first term \( a \) is 8. This initial value is important because it combines with the common difference to define the shape and direction of the entire sequence.
Often, knowing the first term allows you to find any other specific term or even the entire sequence, provided you also know the common difference.
Other exercises in this chapter
Problem 64
Find the coefficient \(a\) of the given term in the expansion of the binomial. Binomial \((x+4)^{12}\) Term \(a x^{4}\)
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Write the first five terms of the sequence (a) using the table feature of a graphing utility and (b) algebraically. (Assume \(n\) begins with 0.) $$a_{n}=\frac{
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In how many different ways can a jury of 12 people be randomly selected from a group of 40 people?
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Using Summation Notation Use summation notation to write the sum. $$5+15+45+\cdots+3645$$
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