Problem 65
Question
Find the exact value of the expression. Use a graphing utility to verify your result. (Hint: Make a sketch of a right triangle.) \(\sin \left(\arctan \frac{4}{3}\right)\)
Step-by-Step Solution
Verified Answer
The exact value of the expression \( \sin \left( \arctan \frac{4}{3} \right) \) is \( \frac{4}{5} \).
1Step 1: Interpret the arctan function in terms of a right triangle
In a right triangle, the tangent of an angle is equal to the ratio of the length of the opposite side to the length of the adjacent side. When it is given that \( \arctan \left( \frac{4}{3}\right) \), it implies a right triangle where the length of the opposite side is 4 and the adjacent side is 3. From this, we can calculate the hypotenuse using the Pythagorean Theorem.
2Step 2: Compute the Hypotenuse
The Pythagorean Theorem states that in a right triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the lengths of the other two sides. In this case, the equation would be: \( \sqrt{4^2 + 3^2} \). Calculating the hypotenuse gives a value of 5.
3Step 3: Determine the sine of the angle
Now that we have all three sides of the triangle, we can find the sine of the angle. Recall that the sine of an angle in a right triangle is defined as the length of the opposite side divided by the length of the hypotenuse. Based on the triangle we've outlined, computing the sine gives: \( \sin \left(\arctan \frac{4}{3} \right) = \frac{4}{5} \).
4Step 4: Verify with a graphing utility
As a final step, the result can be checked with a graphing utility. Calculate the sine of the arctangent of 4/3. The graphing utility should also show a result of \( \frac{4}{5} \), verifying the initial answer.
Key Concepts
Right TriangleArctan FunctionPythagorean Theorem
Right Triangle
Understanding the concept of a right triangle is the first crucial step in solving trigonometric problems using identities. A right triangle is a type of triangle that features one angle exactly equal to 90 degrees. This angle is called the right angle, and it is often denoted by a little square in diagram representations. The other two angles are always acute, meaning they are less than 90 degrees.
Each side of a right triangle has a unique relationship with the angles and are therefore named accordingly:
Each side of a right triangle has a unique relationship with the angles and are therefore named accordingly:
- Opposite side: The side opposite the angle we are focusing on, not the right angle.
- Adjacent side: The side right next to the angle considered, not the hypotenuse.
- Hypotenuse: The longest side opposite the right angle.
Arctan Function
The arctan function, also known as the inverse tangent function, plays an important role in trigonometry. It is used to find an angle whose tangent ratio is a given value. When we talk about \( \arctan \left(\frac{4}{3}\right)\), it refers to an angle \( \theta \) such that the tangent of \( \theta \) is \( \frac{4}{3}\).
This is particularly important when dealing with right triangles because:
This is particularly important when dealing with right triangles because:
- The numerator 4 represents the opposite side of the right triangle.
- The denominator 3 indicates the adjacent side.
Pythagorean Theorem
The Pythagorean Theorem is a powerful tool in trigonometry and geometry. It allows us to determine the length of the hypotenuse in a right triangle when the lengths of the other two sides are known. The theorem states: \[ a^2 + b^2 = c^2 \]where \( a \) and \( b \) are the lengths of the two shorter sides known as the legs, and \( c \) is the hypotenuse.
In solving problems like \( \sin \left(\arctan \frac{4}{3}\right) \), this theorem becomes essential. With our example:
In solving problems like \( \sin \left(\arctan \frac{4}{3}\right) \), this theorem becomes essential. With our example:
- \( a = 4 \) (opposite side)
- \( b = 3 \) (adjacent side)
Other exercises in this chapter
Problem 65
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Find the reference angle \(\theta^{\prime} .\) Sketch \(\theta\) in standard position and label \(\boldsymbol{\theta}^{\prime}\). $$\theta=-292^{\circ}$$
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Use a graphing utility to graph the function. (Include two full periods.) Identify the amplitude and period of the graph. $$y=\cos \left(2 \pi x-\frac{\pi}{2}\r
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Rewrite each angle in radian measure as a multiple of \(\pi .\) (Do not use a calculator.) (a) \(18^{\circ}\) (b) \(-240^{\circ}\)
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