Problem 65
Question
Find all solutions of the quadratic equation. Relate the solutions of the equation to the zeros of an appropriate quadratic function. $$5 x^{2}-2 x+3=0$$
Step-by-Step Solution
Verified Answer
The solutions to the quadratic equation are \(x = 0.2 \pm 0.74833i\) and these also correspond to the zeros of the quadratic function \(f(x) = 5x^{2}-2x+3\).
1Step 1: Identify Coefficients
In the quadratic equation \(5x^{2}-2x+3=0\), the coefficients are \(a = 5\), \(b = -2\), and \(c = 3\).
2Step 2: Apply the Quadratic Formula
Replace \(a\), \(b\), and \(c\) in the quadratic formula \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\) with their corresponding values. Thus we get \(x = \frac{-(-2) \pm \sqrt{(-2)^{2}-4*5*3}}{2*5}\).
3Step 3: Simplify the Result
Simplify the expression to find the roots of the equation. The expression can be simplified to \(x = \frac{2 \pm \sqrt{4-60}}{10}\), and further to \(x = \frac{2 \pm \sqrt{-56}}{10}\). Computing further, \(x = \frac{2 \pm 7.4833i}{10}\), and finally we get \(x = 0.2 \pm 0.74833i\).
4Step 4: Relate to Zeros of the Function
Conclusion: The solutions to the quadratic equation are the same as the zeros of the quadratic function. Therefore, the zeros of the function \(f(x) = 5x^{2} -2x + 3\) are \(x = 0.2 \pm 0.74833i\).
Key Concepts
Quadratic FormulaComplex NumbersZeros of a Function
Quadratic Formula
The quadratic formula is a powerful tool used to solve quadratic equations of the form \( ax^2 + bx + c = 0 \). This formula is particularly useful when factoring is difficult or impossible. The quadratic formula is defined as:
The term under the square root sign, \( b^2 - 4ac \), is called the discriminant. The discriminant tells us about the nature of the roots of the quadratic equation.
- \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \)
The term under the square root sign, \( b^2 - 4ac \), is called the discriminant. The discriminant tells us about the nature of the roots of the quadratic equation.
- If the discriminant is positive, there are two distinct real roots.
- If it is zero, there is one double real root.
- If it's negative, the roots are complex or imaginary numbers.
Complex Numbers
Complex numbers are numbers that comprise a real part and an imaginary part. They are very important when dealing with the square roots of negative numbers, which do not have real solutions. A complex number is usually written in the form \( a + bi \), where \( a \) is the real part and \( b \) is the imaginary part, with \( i \) representing \( \sqrt{-1} \).
Imaginary numbers open up an entirely new way to understand mathematics, essential for solving many kinds of equations, including quadratic equations with negative discriminants.
Imaginary numbers open up an entirely new way to understand mathematics, essential for solving many kinds of equations, including quadratic equations with negative discriminants.
- The imaginary unit \( i \) satisfies \( i^2 = -1 \).
- Complex conjugates are of the form \( a + bi \) and \( a - bi \), which are often observed as solutions in quadratic equations with complex roots.
Zeros of a Function
The zeros of a function are the points where the graph of the function intersects the x-axis. For a quadratic function \( f(x) = ax^2 + bx + c \), the zeros are the solutions to the equation \( ax^2 + bx + c = 0 \), meaning they make the entire function equal to zero.
Finding zeros is a crucial part of analyzing functions because they can also represent x-intercepts and roots.
Finding zeros is a crucial part of analyzing functions because they can also represent x-intercepts and roots.
- In our specific exercise, the quadratic function is \( f(x) = 5x^2 - 2x + 3 \).
- The solutions \( 0.2 \pm 0.74833i \) are the zeros of this function.
- Since these zeros are complex, the graph of this function does not actually cross the x-axis.
Other exercises in this chapter
Problem 65
Graph each quadratic function by finding a suitable viewing window with the help of the TABLE feature of a graphing utility. Also find the vertex of the associa
View solution Problem 65
In Exercises \(49-66,\) let \(f(x)=x^{2}+x, g(x)=\sqrt{x},\) and \(h(x)=-3 x\) Evaluate each of the following. $$(h \circ f)\left(\frac{1}{2}\right)$$
View solution Problem 65
For function of the form \(f(x)=\) \(a x^{2}+b x+c,\) find the discriminant, \(b^{2}-4 a c,\) and use it to determine the number of \(x\) -intercepts of the gra
View solution Problem 65
Applications In this set of exercises, you will use properties of functions to study real-world problems. Stamp Collecting The value of a commemorative stamp \(
View solution