Problem 65
Question
Factor completely, or state that the polynomial is prime. $$ 3 x^{3}-3 x $$
Step-by-Step Solution
Verified Answer
The factored form of this polynomial is \(3x(x+1)(x-1)\)
1Step 1: Identify the Greatest Common Factor (GCF)
The GCF of \(3x^3\) and \(-3x\) is \(3x\).
2Step 2: Factor Out The GCF From Each Term
Factoring out \(3x\) from each term gives \(3x(x^2 - 1)\).
3Step 3: Factor the Difference of Squares
The equation \(x^2 - 1\) is a difference of squares equation and can be factored into \((x+1)(x-1)\).
4Step 4: Write the Complete Factored Form
We write the complete factored form by multiplying the GCF with the factored difference of squares, getting \(3x(x+1)(x-1)\).
Key Concepts
Greatest Common FactorDifference of SquaresAlgebraic Expressions
Greatest Common Factor
Factoring polynomials begins by identifying the Greatest Common Factor (GCF), which is the largest factor shared by each term within the polynomial. When students look at the term 'factoring', they should think of it as a reverse multiplication process—breaking down expressions into simpler parts that can be multiplied to obtain the original expression.
Finding the GCF simplifies the factoring process by reducing the polynomial to an equivalent expression with smaller coefficients and exponents. In our example, the GCF of
After we identify the GCF, we 'factor it out' from each term, which essentially involves dividing each term of the polynomial by the GCF and placing the GCF in front of a set of parentheses. The terms inside the parentheses are what's left after the factor of
Finding the GCF simplifies the factoring process by reducing the polynomial to an equivalent expression with smaller coefficients and exponents. In our example, the GCF of
3x^3 and -3x is 3x; this is because 3x is the largest expression that divides evenly into both terms.After we identify the GCF, we 'factor it out' from each term, which essentially involves dividing each term of the polynomial by the GCF and placing the GCF in front of a set of parentheses. The terms inside the parentheses are what's left after the factor of
3x is taken out of each term of the original expression.Difference of Squares
The Difference of Squares is an essential algebraic concept for students to grasp when factoring certain types of polynomials. It refers to expressions that can be written in the form
These expressions are special because they can always be factored into the product of two binomials:
a^2 - b^2, representing the difference between two perfect squares. Prime examples include x^2 - 1, x^2 - 9, or 4x^2 - 16.These expressions are special because they can always be factored into the product of two binomials:
(a + b)(a - b). For instance, the expression x^2 - 1 can be viewed as the difference between the square of x and the square of 1. By employing the Difference of Squares formula, the factored form of x^2 - 1 becomes (x + 1)(x - 1). This method assists in simplifying equations and solving problems with squared terms.Algebraic Expressions
Algebraic expressions are combinations of variables, numbers, and at least one arithmetic operation. In our original exercise,
Algebraic expressions can vary greatly in complexity—ranging from simple monomials like
Once the foundational aspects are recognized, algebraic expressions can be factored, simplified, and solved to reveal useful information about the relationships between the variables and constants they contain.
3x^3 - 3x is an algebraic expression with x as the variable. The process of factoring algebraic expressions is much like finding the puzzle pieces that, when combined, will form the given expression.Algebraic expressions can vary greatly in complexity—ranging from simple monomials like
3x, to binomials such as (x + 1), up to polynomials with many terms. Factoring an algebraic expression requires a fundamental understanding of arithmetic operations, exponent rules, and the application of factoring strategies like finding the GCF and employing the Difference of Squares.Once the foundational aspects are recognized, algebraic expressions can be factored, simplified, and solved to reveal useful information about the relationships between the variables and constants they contain.
Other exercises in this chapter
Problem 64
Simplify each complex rational expression. $$\frac{1-\frac{1}{x}}{x y}$$
View solution Problem 64
Simplify each exponential expression in Exercises 23–64. $$\left(\frac{4 a^{-5} b^{3}}{12 a^{3} b^{-5}}\right)^{0}$$
View solution Problem 65
Evaluate each expression or indicate that the root is not a real number. $$\sqrt[5]{-\frac{1}{32}}$$
View solution Problem 65
Perform the indicated operations Indicate the degree of the resulting polynomial. $$ \left(3 x^{4} y^{2}+5 x^{3} y-3 y\right)-\left(2 x^{4} y^{2}-3 x^{3} y-4 y+
View solution