Problem 65
Question
Factor by grouping. $$k t+7 t-5 k-35$$
Step-by-Step Solution
Verified Answer
The given expression is factored by grouping as follows:
\(kt + 7t - 5k - 35 = (kt + 7t) + (-5k - 35) = t(k + 7) - 5(k + 7) = (k + 7)(t - 5)\)
1Step 1: 1. Group the terms
First, we need to group the terms in a way that will make factoring easier. Look for terms that share common factors. In this case, the given expression is:
$$kt + 7t - 5k - 35$$
We can group the terms as follows:
$$(kt + 7t) + (-5k - 35)$$
2Step 2: 2. Factor out the common factors
Now, we need to factor out the common factors from each group. In the first group, there is a common factor of 't', and in the second group, there is a common factor of '-5'. So we can rewrite the expression as:
$$t(k + 7) - 5(k + 7)$$
3Step 3: 3. Factor out the common binomial factor
We now have a common binomial factor, \((k + 7)\), in both terms. We can factor out this binomial factor and rewrite the expression:
$$(k + 7)(t - 5)$$
Now the expression has been factored by grouping. The final result is:
$$(k + 7)(t - 5)$$
Key Concepts
Common FactorsBinomial FactorAlgebraic Expressions
Common Factors
In algebra, finding common factors is a crucial step in simplifying expressions and solving equations. A common factor is a term that is shared by all terms in an expression. Identifying these can make the process of factoring much simpler.
For the expression given in the exercise, we have:
For the expression given in the exercise, we have:
- In the first group \((kt + 7t)\), the common factor is \(t\).
- In the second group \((-5k - 35)\), the common factor is \(-5\).
Binomial Factor
A binomial factor comes into play when we have grouped terms that share a common binomial expression. Recognizing a binomial factor helps in further simplifying complex algebraic expressions.
After extracting common factors from each part of our grouped expression, we noticed a shared binomial factor: \((k + 7)\). This commonality allows us to further simplify our expression:
After extracting common factors from each part of our grouped expression, we noticed a shared binomial factor: \((k + 7)\). This commonality allows us to further simplify our expression:
- Factor out \((k + 7)\) which appears in both terms: \(t(k + 7)\) and \(-5(k + 7)\).
- This leads to the factorizable form \((k + 7)(t - 5)\).
Algebraic Expressions
Algebraic expressions are combinations of numbers, variables, and operations that together form a mathematical sentence. Understanding how to manipulate them is key to mastering algebra.
In the given exercise, we start with the expression \(kt + 7t - 5k - 35\). To manage such an expression, one should:
In the given exercise, we start with the expression \(kt + 7t - 5k - 35\). To manage such an expression, one should:
- Identify and group terms that can be paired due to shared factors.
- Use the properties of common factors and binomial factors to reduce the complexity of the expression.
- Transform the expression into a factored form, simplifying it.
Other exercises in this chapter
Problem 65
Factor completely. $$16 h^{4}-g^{4}$$
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The following equations are not quadratic but can be solved by factoring and applying the zero product rule. Solve each equation. $$m^{3}=64 m$$
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Factor completely. $$8 c^{2} d^{3}+4 c^{2} d^{2}-60 c^{2} d$$
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Factor completely, if possible. Begin by asking yourself, "Can I factor out a GCF?" $$7 c^{3} d^{2}-7 c^{2} d^{2}-14 c d^{2}$$
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