Problem 65
Question
Factor any perfect square trinomials, or state that the polynomial is prime. $$16 x^{2}-40 x y+25 y^{2}$$
Step-by-Step Solution
Verified Answer
The factorization of the given perfect square trinomial \(16x^{2}-40xy+25y^{2}\) is \((4x-5y)^{2}\)
1Step 1: Inspect the terms
Observe the given polynomial \(16x^{2}-40xy+25y^{2}\). In comparison to the general perfect square trinomial \(a^{2}-2ab+b^{2}\), it can be seen that \(a^{2} = 16x^{2}\), \(-2ab = -40xy\) and \(b^{2} = 25y^{2}\)
2Step 2: Find the square roots
Find the square root of \(a^{2}\) and \(b^{2}\) to get 'a' and 'b' respectively. For \(a^{2} = 16x^{2}\), 'a' is 4x. For \(b^{2} = 25y^{2}\), 'b' is 5y.
3Step 3: Check validity
To ensure the terms are correct, compute \(2*a*b\), which should equal to the second term of the trinomial (-40xy).
4Step 4: Write down the final factorization
If the terms satisfy the rules of perfect square trinomials, then we can write down the factorization as \((a-b)^{2}\). In our case, this would be \((4x-5y)^{2}\).
Key Concepts
Polynomial FactorizationAlgebraic ExpressionsSquare RootsTrinomial Structure
Polynomial Factorization
Factoring polynomials is an essential technique in algebra that simplifies expressions by expressing them as a product of their factors. This is especially useful for solving equations and analyzing their roots. For a polynomial to be factored, it usually means rewriting it by identifying and separating common factors.
There are several methods to factor polynomials, including:
- Extracting common factors.
- Grouping terms.
- Factoring quadratics into binomials.
- Recognizing special products like perfect square trinomials and difference of squares.
Algebraic Expressions
Algebraic expressions are combinations of numbers, variables, and operations. They form the basic building blocks of algebra, representing real-world quantities and relationships.In the context of our problem, the expression \(16x^{2} - 40xy + 25y^{2}\) is an example of a polynomial, where:
- Coefficients are the numerical parts, like 16, -40, and 25.
- Variables are the alphabetic representations like \(x\) and \(y\).
- Terms are the separate additive components of the expression, like \(16x^{2}\), \(-40xy\), and \(25y^{2}\).
Square Roots
Square roots are one of the fundamental operations in algebra, necessary for solving many equations, and are particularly significant in the factorization of perfect square trinomials.A square root of a number \(n\) is a value that, when multiplied by itself, gives \(n\). In the context of our exercise, finding the square roots of \(16x^{2}\) and \(25y^{2}\) was key:
- The square root of \(16x^{2}\) is \(4x\), since \((4x) \times (4x) = 16x^{2}\).
- The square root of \(25y^{2}\) is \(5y\), since \((5y) \times (5y) = 25y^{2}\).
Trinomial Structure
The structure of a trinomial is composed of three terms, usually expressed in the form \(ax^2 + bx + c\). Understanding this structure is crucial to recognizing perfect square trinomials and simplifying them.For the trinomial given in the exercise, identify it as a perfect square trinomial by matching it to the form \(a^2 - 2ab + b^2\). In this case:
- \(a^2 = 16x^{2}\)
- \(-2ab = -40xy\)
- \(b^2 = 25y^{2}\)
Other exercises in this chapter
Problem 65
Factor completely. $$x^{5}+3 x^{4} y-4 x^{3} y^{2}$$
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Solve each equation and check your solutions. $$(x-2)^{2}-5(x-2)+6=0$$
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Factor completely. $$9 y^{2}+33 y-60$$
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Now let's move on to factorizations that may require two or more techniques. Factor completely, or state that the polynomial is prime. Check factorizations usin
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