Problem 65
Question
Convert the polar equation to rectangular form. $$r=4 \sin \theta$$
Step-by-Step Solution
Verified Answer
The rectangular form of the polar equation \(r = 4\sin(\theta)\) is \(yx^2 = 4x^2 - 4(x^2 + y^2)\), after substituting and simplifying.
1Step 1: Review the conversion relation between coordinate systems
The connection between polar and rectangular coordinates is given by \(x = r\cos(\theta)\) and \(y = r\sin(\theta)\).
2Step 2: Substitute the given polar equation into rectangular form
The given polar equation is \(r = 4\sin(\theta)\). We can substitute \(r\) into the expression for \(y\) as follows: \(y = r\sin(\theta) = 4\sin^2(\theta)\).
3Step 3: Reduce the equation
To obtain the most common representation of this equation, use the Pythagorean identity \(1-\cos^2(\theta)=\sin^2(\theta)\). This will give us: \(y = 4(1-\cos^2(\theta))\). Next, substitute \(x = r\cos(\theta)\) into our equation to replace \(\cos(\theta)\). Solving for r, we find that \(r = \frac{x}{\cos(\theta)}\). Substituting this gives: \(y = 4(1-(r/x)^2)\). This needs to be further reduced in order to give x and y in terms of r.
4Step 4: Solve the final equation in terms of x and y
To get y in terms of x, multiply both sides by x^2: \(yx^2 = 4x^2 - 4r^2\). Our equation: \(r^2 = x^2 + y^2\), will replace \(r^2\), so finally we get \(yx^2 = 4x^2 - 4(x^2 + y^2)\).
Other exercises in this chapter
Problem 64
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Classify the graph of the equation as a circle, a parabola, an ellipse, or a hyperbola. \(y^{2}-x^{2}+2 x-6 y-8=0\)
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Determine whether the statement is true or false. Justify your answer. The two sets of parametric equations \(x=t, y=t^{2}+1\) and \(x=3 t, \quad y=9 t^{2}+1\)
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Find the vertex, focus, and directrix of the parabola and sketch its graph. Use a graphing utility to verify your graph. $$x^{2}+6 y=0$$
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