Problem 65
Question
Choose a method and solve the quadratic equation. Explain your choice. $$ 3 x^{2}+5 x-12=0 $$
Step-by-Step Solution
Verified Answer
The solutions of the quadratic equation \(3x^{2}+5x-12=0\) are \(x=-1\) and \(x=4\).
1Step 1: Identification of Parameters
Firstly, identify the parameters in the quadratic equation. In this case, \(a=3\), \(b=5\), and \(c=-12\) from the equation \(3x^{2}+5x-12=0\)
2Step 2: Calculation of Discriminant
Then, calculate the discriminant which is \(b^{2}-4ac\). Substitute \(a=3\), \(b=5\), and \(c=-12\) into this formula. The result is \(D= (5)^{2} - 4*3*(-12) = 25 +144 = 169\)
3Step 3: Application of Quadratic Formula
Now, apply the quadratic formula \(x=\frac{-b\pm \sqrt{b^{2}-4ac}}{2a}\). Substitute \(a=3\), \(b=5\), and \(D=169\) into this equation, and solve for \(x\). The solutions of this equation will be \(x1=\frac{-5+ \sqrt{169}}{2*3} = -1\) and \(x2=\frac{-5- \sqrt{169}}{2*3}= 4\)
Key Concepts
Quadratic FormulaDiscriminantRoots of Quadratic Equation
Quadratic Formula
The quadratic formula is a powerful tool for solving quadratic equations of the form \(ax^2 + bx + c = 0\). It provides a method for finding the roots of the equation, which are the values of \(x\) that satisfy the equation. The formula itself is:
\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]
Using this formula allows you to find the roots even when factoring the quadratic equation is not straightforward. By directly substituting the coefficients \(a\), \(b\), and \(c\) from the equation into the formula, you can systematically arrive at the root values.
Some key features of the quadratic formula include:
\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]
Using this formula allows you to find the roots even when factoring the quadratic equation is not straightforward. By directly substituting the coefficients \(a\), \(b\), and \(c\) from the equation into the formula, you can systematically arrive at the root values.
Some key features of the quadratic formula include:
- It works for every quadratic equation, regardless of whether the roots are real, complex, or irrational.
- The \(\pm\) symbol indicates that there are usually two solutions, arising from the two possible values for the square root.
Discriminant
The discriminant is a crucial component of the quadratic formula. It is the part under the square root: \(b^2 - 4ac\). The discriminant determines the nature and number of the roots of a quadratic equation.
Here's what the discriminant tells us about the roots of the equation:
Here's what the discriminant tells us about the roots of the equation:
- If the discriminant is positive, \(b^2 - 4ac > 0\), there are two distinct real roots. This happens because the square root of a positive number gives a positive and a negative result, contributing to two solutions.
- If the discriminant is zero, \(b^2 - 4ac = 0\), there is exactly one real root. Also known as a repeated or double root, it represents the point where the graph of the equation just touches the x-axis.
- If the discriminant is negative, \(b^2 - 4ac < 0\), there are no real roots. Instead, the roots are complex numbers, which means the graph does not intersect the x-axis.
Roots of Quadratic Equation
The roots of a quadratic equation are the solutions you find by setting the quadratic expression equal to zero and solving for \(x\). They represent the x-values where the graph of the quadratic equation touches or crosses the x-axis.
The quadratic equation \(ax^2 + bx + c = 0\) might have:
Understanding roots is pivotal as they provide critical points that describe the solution space of quadratic equations.
The quadratic equation \(ax^2 + bx + c = 0\) might have:
- Two distinct real roots, if the discriminant \(b^2 - 4ac\) is positive.
- One real root if the discriminant equals zero, meaning the graph is tangent to the x-axis.
- Two complex roots if the discriminant is negative, indicating no real solutions.
Understanding roots is pivotal as they provide critical points that describe the solution space of quadratic equations.
Other exercises in this chapter
Problem 64
Simplify the radical expression. $$\sqrt{175}$$
View solution Problem 65
Simplify the expression. $$ \frac{3}{x}+\frac{x+9}{x} $$
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Solve the equation by factoring. $$ x^{2}+2 x-15=0 $$
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Solve the equation. Write the solutions as integers if possible. Otherwise, write them as radical expressions. $$ -16 x^{2}+48=0 $$
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