Problem 64
Question
Which one of the following statements is true? (a) The dipole moment of \(\mathrm{NF}_{3}\) is more than \(\mathrm{NH}_{3}\) (b) The dipole moment of \(\mathrm{NF}_{3}\) is less than \(\mathrm{NH}_{3}\) (c) The dipole moment of \(\mathrm{NH}_{3}\) is zero (d) The dipole moment of \(\mathrm{NF}_{3}\) is equal to \(\mathrm{NH}_{3}\)
Step-by-Step Solution
Verified Answer
The correct statement is (b): The dipole moment of \(\mathrm{NF}_{3}\) is less than \(\mathrm{NH}_{3}\).
1Step 1: Understanding Dipole Moment
The dipole moment is a measure of the separation of positive and negative charges in a molecule. It depends on both the magnitude of the charges and the distance between them. It is a vector quantity, meaning it has both direction and magnitude.
2Step 2: Structure of NH3 and NF3
Ammonia (\(\mathrm{NH}_{3}\)) has a trigonal pyramidal shape, with nitrogen at the center and hydrogen atoms forming the base. The lone pair of electrons on nitrogen pushes the hydrogen atoms downwards. In \(\mathrm{NF}_{3}\), nitrogen is also in the center with a lone pair, forming the same trigonal pyramidal shape, but with fluorine atoms.
3Step 3: Direction of Dipole Moment
In \(\mathrm{NH}_{3}\), the dipole moment points from the nitrogen atom towards the hydrogen atoms since nitrogen is more electronegative than hydrogen. This results in a net dipole moment directed upwards. In \(\mathrm{NF}_{3}\), the dipole moment vectors are directed from the nitrogen towards the fluorine atoms, but since fluorine is more electronegative than nitrogen, the net dipole moment is directed downwards.
4Step 4: Comparison of Dipole Moments
For \(\mathrm{NH}_{3}\), the upward-directed dipole moment results in a relatively high net dipole moment because the vectors add in the same direction as the lone pair. However, in \(\mathrm{NF}_{3}\), the strong electronegativity of fluorine causes the dipole moments of the bonds to oppose the lone pair, reducing the net dipole moment.
5Step 5: Determining the Correct Statement
Based on the analysis, \(\mathrm{NH}_{3}\) has a larger dipole moment than \(\mathrm{NF}_{3}\) due to the addition of its molecular dipole vectors aligning with the lone pair of electrons, resulting in option (b) being correct: "The dipole moment of \(\mathrm{NF}_{3}\) is less than \(\mathrm{NH}_{3}\)."
Key Concepts
ElectronegativityMolecular GeometryTrigonal Pyramidal Shape
Electronegativity
Electronegativity is a key concept in understanding molecular interactions. It is the ability of an atom to attract shared electrons towards itself in a chemical bond. Different elements have varying electronegativity values, with fluorine being the most electronegative element on the periodic table.
In molecules like \(F_3\) and \(H_3\), electronegativity plays a crucial role in determining the direction and magnitude of their dipole moments.
This is because the difference in electronegativity between bonded atoms leads to a polar bond.
For instance, ammonia (\(NH_3\)) comprises nitrogen and hydrogen atoms, where nitrogen is more electronegative than hydrogen. This difference causes a partial negative charge on nitrogen and a partial positive charge on each hydrogen, resulting in a net dipole moment directed upwards.
In molecules like \(F_3\) and \(H_3\), electronegativity plays a crucial role in determining the direction and magnitude of their dipole moments.
This is because the difference in electronegativity between bonded atoms leads to a polar bond.
For instance, ammonia (\(NH_3\)) comprises nitrogen and hydrogen atoms, where nitrogen is more electronegative than hydrogen. This difference causes a partial negative charge on nitrogen and a partial positive charge on each hydrogen, resulting in a net dipole moment directed upwards.
- Electronegativity increases across a period from left to right.
- It generally decreases as you move down a group due to increasing atomic size.
Molecular Geometry
Molecular geometry is the three-dimensional arrangement of atoms within a molecule, dictated by electron pair repulsion and the number of atoms attached to a central atom.
Understanding molecular geometry is critical for predicting the behavior and properties of molecules, including polarity and reactivity.
For ammonia (\(NH_3\) and nitrogen trifluoride (\(NF_3\)), both compounds exhibit a trigonal pyramidal shape.
This geometry arises due to the presence of three bonding pairs and one lone pair of electrons around the central nitrogen atom.
Understanding molecular geometry is critical for predicting the behavior and properties of molecules, including polarity and reactivity.
For ammonia (\(NH_3\) and nitrogen trifluoride (\(NF_3\)), both compounds exhibit a trigonal pyramidal shape.
This geometry arises due to the presence of three bonding pairs and one lone pair of electrons around the central nitrogen atom.
- Electron pairs, both bonding and non-bonding, repel each other.
- This repulsion affects the positioning of the atoms to minimize energy and maximize stability.
Trigonal Pyramidal Shape
The trigonal pyramidal shape is characteristic of molecules having a central atom surrounded by three atoms and a lone pair. This shape is a result of the VSEPR (Valence Shell Electron Pair Repulsion) theory, which predicts the arrangement of electron pairs around a central atom to minimize repulsion.
In both ammonia (\(NH_3\) and nitrogen trifluoride (\(NF_3\)), the central nitrogen atom exhibits this trigonal pyramidal shape.
The lone pair of electrons plays a crucial role in shaping these molecules as it exerts a greater repulsive force than bonded pairs, pushing the other atoms downward.
Conversely, in \(F_3\), the stronger electronegative fluorine atoms oppose the lone pair's influence, thus diminishing the net dipole compared to \(H_3\). Understanding the trigonal pyramidal shape helps explain the distinct dipole moment differences between these two compounds.
In both ammonia (\(NH_3\) and nitrogen trifluoride (\(NF_3\)), the central nitrogen atom exhibits this trigonal pyramidal shape.
The lone pair of electrons plays a crucial role in shaping these molecules as it exerts a greater repulsive force than bonded pairs, pushing the other atoms downward.
- This results in a pyramid-like structure with the lone pair at the apex.
- Overall dipole moments result from both the geometry and electronegativity differences.
Conversely, in \(F_3\), the stronger electronegative fluorine atoms oppose the lone pair's influence, thus diminishing the net dipole compared to \(H_3\). Understanding the trigonal pyramidal shape helps explain the distinct dipole moment differences between these two compounds.
Other exercises in this chapter
Problem 62
Which one of the following molecules has the smallest bond angle? (a) \(\mathrm{H}_{2} \mathrm{O}\) (b) \(\mathrm{NH}_{3}\) (c) \(\mathrm{H}_{2} \mathrm{Se}\) (
View solution Problem 63
In which of the following molecules the central atom does not follow the octet rule? (a) \(\mathrm{CO}_{2}\) (b) \(\mathrm{H}_{2} \mathrm{~S}\) (c) \(\mathrm{BF
View solution Problem 65
Bond angle in water is (a) \(90^{\circ}\) (b) \(104.5^{\circ}\) (c) \(109.5^{\circ}\) (d) \(120^{\circ}\)
View solution Problem 66
Which of the following is a linear molecule? (a) \(\mathrm{SO}_{2}\) (b) \(\mathrm{CH}_{4}\) (c) \(\mathrm{H}_{2} \mathrm{O}\) (d) \(\mathrm{BeCl}_{2}\)
View solution