Problem 64
Question
Which of the following is formed when silver nitrate is treated with caustic soda? (a) \(\mathrm{Ag}_{3} \mathrm{~N}\) (b) \(\mathrm{Ag}\) (c) \(\mathrm{AgNO}_{2}\) (d) \(\mathrm{Ag}_{2} \mathrm{O}\)
Step-by-Step Solution
Verified Answer
Silver oxide, \( \mathrm{Ag}_{2} \mathrm{O} \), is formed.
1Step 1: Identify the Reaction
We need to determine the product of the reaction between silver nitrate (AgNO₃) and caustic soda (NaOH). This is a typical double displacement reaction where the ions exchange partners.
2Step 2: Write the Chemical Equation
The chemical equation for the reaction is:\[ \mathrm{AgNO}_{3 (aq)} + \mathrm{NaOH}_{(aq)} \rightarrow \mathrm{AgOH}_{(s)} + \mathrm{NaNO}_{3(aq)} \]Here, silver hydroxide (AgOH) will initially form.
3Step 3: Understand the Instability of AgOH
Silver hydroxide (AgOH) is not stable. It decomposes to form silver oxide (Ag₂O) and water:\[ 2 \mathrm{AgOH} \rightarrow \mathrm{Ag}_{2} \mathrm{O} + \mathrm{H}_{2} \mathrm{O} \]
4Step 4: Identify the Final Product
The final product, after the decomposition of AgOH, is silver oxide (Ag₂O). Thus, the product formed when silver nitrate is treated with caustic soda is silver oxide.
Key Concepts
Silver NitrateCaustic SodaChemical EquationSilver Oxide
Silver Nitrate
Silver nitrate, represented by the formula \( \mathrm{AgNO}_{3} \), is a versatile compound used in many chemical reactions.
It is an ionic compound composed of one silver cation \( \mathrm{Ag}^{+} \) and one nitrate anion \( \mathrm{NO}_{3}^{-} \). Silver nitrate is important in laboratories because it can be used to test for the presence of chloride ions in a solution among other applications.
It is an ionic compound composed of one silver cation \( \mathrm{Ag}^{+} \) and one nitrate anion \( \mathrm{NO}_{3}^{-} \). Silver nitrate is important in laboratories because it can be used to test for the presence of chloride ions in a solution among other applications.
- Silver nitrate is typically found as a white crystalline solid.
- It dissolves easily in water, making it an aqueous solution when mixed with a suitable solvent.
- The nitrate ion is a good leaving group, facilitating reactions such as double displacement.
Caustic Soda
Caustic soda is more commonly known as sodium hydroxide, and its chemical formula is \( \mathrm{NaOH} \).
It is a strong base widely employed in chemical industries and laboratories. Caustic soda is known for its ability to react with various compounds, especially those containing metals, to form precipitates.
It is a strong base widely employed in chemical industries and laboratories. Caustic soda is known for its ability to react with various compounds, especially those containing metals, to form precipitates.
- It appears as a white solid, which is also highly soluble in water, forming a basic solution.
- Sodium hydroxide is crucial for processes such as soap making, paper production, and in chemical reactions for neutralization.
- In the described reaction, its role is to provide hydroxide ions \( \mathrm{OH}^{-} \) necessary for forming the intermediate, silver hydroxide.
Chemical Equation
A chemical equation represents the reactants and products in a chemical reaction using chemical formulas.
It shows the conversion and transformation of substances through reactant-product relationships.
In the case of silver nitrate and caustic soda reacting, the initial chemical equation is:
\[ \mathrm{AgNO}_{3(aq)} + \mathrm{NaOH}_{(aq)} \rightarrow \mathrm{AgOH}_{(s)} + \mathrm{NaNO}_{3(aq)} \]
This illustrates a double displacement reaction where an exchange of ions occurs. The silver cation \( \mathrm{Ag}^{+} \) and the hydroxide \( \mathrm{OH}^{-} \) come together to form silver hydroxide \( \mathrm{AgOH} \), and sodium nitrate \( \mathrm{NaNO}_{3} \) is left formed in the solution.
Important points to remember:
It shows the conversion and transformation of substances through reactant-product relationships.
In the case of silver nitrate and caustic soda reacting, the initial chemical equation is:
\[ \mathrm{AgNO}_{3(aq)} + \mathrm{NaOH}_{(aq)} \rightarrow \mathrm{AgOH}_{(s)} + \mathrm{NaNO}_{3(aq)} \]
This illustrates a double displacement reaction where an exchange of ions occurs. The silver cation \( \mathrm{Ag}^{+} \) and the hydroxide \( \mathrm{OH}^{-} \) come together to form silver hydroxide \( \mathrm{AgOH} \), and sodium nitrate \( \mathrm{NaNO}_{3} \) is left formed in the solution.
Important points to remember:
- A balanced chemical equation ensures the conservation of mass according to the law of conservation of matter.
- This reaction demonstrates ionic exchange that is crucial in understanding double displacement reactions.
Silver Oxide
Silver oxide, represented by the formula \( \mathrm{Ag}_{2} \mathrm{O} \), is a result of the decomposition of silver hydroxide in this reaction.
Silver hydroxide is initially formed when silver nitrate reacts with caustic soda, but due to its instability, it breaks down.
The decomposition reaction is:
\[ 2\, \mathrm{AgOH} \rightarrow \mathrm{Ag}_{2}\, \mathrm{O} + \mathrm{H}_{2}\, \mathrm{O} \]
This means that two molecules of silver hydroxide decompose to form silver oxide and water.
Notable characteristics of silver oxide include:
Silver hydroxide is initially formed when silver nitrate reacts with caustic soda, but due to its instability, it breaks down.
The decomposition reaction is:
\[ 2\, \mathrm{AgOH} \rightarrow \mathrm{Ag}_{2}\, \mathrm{O} + \mathrm{H}_{2}\, \mathrm{O} \]
This means that two molecules of silver hydroxide decompose to form silver oxide and water.
Notable characteristics of silver oxide include:
- It appears as a fine black or dark brown powder.
- Silver oxide is used in some batteries and can also be a catalyst in certain reactions.
- Understanding its formation is key in reaction analysis involving silver compounds.
Other exercises in this chapter
Problem 62
With \(\mathrm{NH}_{4} \mathrm{OH}\), the silver nitrate is decomposed to give a brown precipitate of (a) \(\mathrm{Ag}_{2} \mathrm{O}\) (b) \(\mathrm{AgO}\) (c
View solution Problem 63
The solubility of AgBr in hypo is due to the formation of (a) \(\mathrm{Ag}_{2} \mathrm{~S}_{2} \mathrm{O}_{3}\) (b) \(\left[\mathrm{Ag}\left(\mathrm{S}_{2} \ma
View solution Problem 65
Parke's process is used (a) to extract Cu using \(\mathrm{CuFeS}_{2}\) (b) to extract Ag from argenti ferrous lead (c) to extract \(\mathrm{Ag}\) by forming ama
View solution Problem 66
In the extraction of silver, \(\mathrm{Ag}_{2} \mathrm{~S}\) is dissolved in (a) \(\mathrm{HNO}_{3}\) (b) \(\mathrm{H}_{2} \mathrm{SO}_{4}\) (c) \(\mathrm{HCl}\
View solution