Problem 64
Question
What is the difference between \(\alpha\) -glucose and \(\beta\) -glucose? Show the condensation of two glucose molecules to form a disaccharide with an \(\alpha\) linkage; with a \(\beta\) linkage.
Step-by-Step Solution
Verified Answer
The difference between α-glucose and β-glucose lies in the position of the hydroxyl group on the first carbon atom in their ring structures. In α-glucose, the hydroxyl group is in the axial position, and in β-glucose, it's in the equatorial position. When two α-glucose molecules form a disaccharide, it results in an α-linkage and the formation of maltose (α-1,4-glycosidic bond). When two β-glucose molecules form a disaccharide, it results in a β-linkage and the formation of cellobiose (β-1,4-glycosidic bond). These different bond orientations affect the properties of disaccharides, including how they are recognized and broken down by different enzymes.
1Step 1: Understand α-glucose and β-glucose
α-glucose and β-glucose are isomers of glucose, which means they have the same chemical formula, but their atomic arrangements are different. The primary difference between these two molecules is the position of the hydroxyl group (OH) on the first carbon atom (C1) in the ring structure of glucose. In α-glucose, the hydroxyl group is below the plane of the ring (in the axial position), while in β-glucose, the hydroxyl group is above the plane of the ring (in the equatorial position).
2Step 2: Illustrate α-linkage and β-linkage in the formation of disaccharides
A disaccharide is formed when two monosaccharides (in this case, glucose molecules) are joined together through a glycosidic bond. The bond forms between the hydroxyl group on the first carbon atom (C1) of one glucose molecule and the hydroxyl group on the fourth carbon atom (C4) of the other glucose molecule, releasing a water molecule in the process. This is called a condensation reaction.
α-linkage: When two α-glucose molecules are joined together by a glycosidic bond, it results in an α-linkage. The disaccharide formed is maltose, which has an α-1,4-glycosidic bond. The process can be represented as:
α-glucose + α-glucose → maltose + water
β-linkage: When two β-glucose molecules are joined together by a glycosidic bond, it results in a β-linkage. The disaccharide formed is cellobiose, which has a β-1,4-glycosidic bond. The process can be represented as:
β-glucose + β-glucose → cellobiose + water
3Step 3: Observe the differences in disaccharide structure
The disaccharides formed from α-glucose (maltose) and β-glucose (cellobiose) differ in their glycosidic bond orientation due to the difference in the position of the hydroxyl group on the first carbon atom in the ring structure of glucose.
In maltose, the α-1,4-glycosidic bond exhibits a downward (axial) orientation due to the α-glucose molecule. In contrast, the β-1,4-glycosidic bond in cellobiose has an upward (equatorial) orientation because of the β-glucose molecule.
It's important to note that these different bond orientations significantly affect the properties of disaccharides, including how they are recognized and broken down by different enzymes in the body.
Other exercises in this chapter
Problem 62
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