Problem 64
Question
Use transformations to sketch a graph of \(f\). \(f(x)=2+\sqrt{-(x-3)}\)
Step-by-Step Solution
Verified Answer
The graph is a leftward curve above \(y=2\) starting from \((3, 2)\).
1Step 1: Identify the Base Function
The base function for this exercise is the square root function, which is \(g(x) = \sqrt{x}\). Before we apply any transformations, \(g(x)\) is defined only for \(x \geq 0\) and is a curve starting at the origin and increasing to the right.
2Step 2: Apply Horizontal Transformation
The expression under the square root, \(-x + 3\) or \(-(x-3)\), results in a reflection across the y-axis and a horizontal shift. The negative sign reflects the graph of \(g(x)\) across the line \(x = 3\). This makes the function decrease leftward starting from \(x = 3\), technically becoming \(h(x) = \sqrt{-(x-3)}\).
3Step 3: Determine the Domain
To ensure the expression under the square root is non-negative, set \(-x + 3 \geq 0\), meaning \(x \leq 3\). The domain of \(f(x)\) is therefore \(x \leq 3\).
4Step 4: Apply Vertical Transformation
The function \(f(x) = 2 + \sqrt{-(x-3)}\) adds 2 to each \(y\)-coordinate of the graph of \(h(x)\). This vertical shift moves the whole graph up by 2 units.
5Step 5: Sketch the Graph
To sketch the graph, plot starting from the point \((3, 2)\) and moving leftward, since the function decreases with decreasing \(x\). The curve starts at the point \((3, 2)\), decreases and extends leftwards, remaining above the line \(y = 2\).
Key Concepts
Square Root FunctionHorizontal ShiftVertical TransformationDomain of a Function
Square Root Function
The square root function is one of the basic functions in mathematics. It is typically represented as \( g(x) = \sqrt{x} \). This function is defined only for non-negative values of \( x \) because you cannot take the square root of a negative number without entering the realm of complex numbers.
- The graph of a square root function is a curve that starts at the origin \((0,0)\).
- It continually rises as it moves to the right.
Horizontal Shift
Horizontal shifts involve moving the graph of a function left or right along the x-axis. For the given function, \( f(x) = 2 + \sqrt{-(x-3)} \), there is a transformation inside the square root, specifically \(-(x-3)\).
- The minus sign in front of \( x \) results in a reflection across the vertical line \( x = 3 \).
- Effectively, this causes a horizontal shift of the graph to the left from \( x = 3 \).
Vertical Transformation
Vertical transformations change the position of a graph vertically on the coordinate plane. With \( f(x) = 2 + \sqrt{-(x-3)} \), the '2' outside the square root indicates a vertical shift.
- This adds 2 to every \( y \)-value of the transformed square root function.
- It's like taking the graph from the horizontal shift and lifting it upwards by 2 units.
Domain of a Function
The domain of a function is the set of all possible input values \( x \) that it can accept without resulting in undefined or non-real outputs. For \( f(x) = 2 + \sqrt{-(x-3)} \), to ensure the square root is computing a real number, the expression inside must be non-negative.
- Setting \(-x + 3 \geq 0\) leads to solving \( x \leq 3 \).
Other exercises in this chapter
Problem 63
Find the domain of the function. Write your answer in set-builder notation. $$ g(t)=\frac{5-t}{t^{2}-t-2} $$
View solution Problem 64
A rectangle is 4 feet longer than it is wide. If the area of the rectangle must be less than or equal to 672 square feet, find the possible values for the width
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Solve. Write answers in standard form. $$ 2 x^{2}+x+1=0 $$
View solution Problem 64
Find the domain of the function. Write your answer in set-builder notation. $$ g(t)=\frac{t+1}{2 t^{2}-11 t-21} $$
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