Problem 64
Question
Suppose \(4 x+3 y=12 .\) Find \(x\) if: $$y=-4$$
Step-by-Step Solution
Verified Answer
When \(y = -4\), \(x = 6\).
1Step 1: Substitute the Given Value for y
Start by substituting the given value of \(y = -4\) into the equation \(4x + 3y = 12\). This substitution transforms the equation into \(4x + 3(-4) = 12\).
2Step 2: Simplify the Equation
Multiply 3 by -4 to simplify the equation: \(4x - 12 = 12\).
3Step 3: Isolate the Term with x
Add 12 to both sides of the equation to isolate the term containing \(x\). This results in \(4x = 24\).
4Step 4: Solve for x
Divide both sides of the equation by 4 to solve for \(x\). Thus, \(x = \frac{24}{4} = 6\).
Key Concepts
Linear EquationsSolving for VariablesAlgebraic Substitution
Linear Equations
A linear equation is a type of equation where the highest power of the variable is one. You can recognize them by their straightforward form, typically written as:
The beauty of linear equations lies in their simplicity. They describe straight lines in geometry when plotted on a graph. This is because the relationship between the variables is consistent and does not change.
Linear equations are foundational in algebra, providing the basis for understanding more complex equations and functions later on.
- \( ax + by = c \)
The beauty of linear equations lies in their simplicity. They describe straight lines in geometry when plotted on a graph. This is because the relationship between the variables is consistent and does not change.
Linear equations are foundational in algebra, providing the basis for understanding more complex equations and functions later on.
Solving for Variables
Solving for variables is all about finding the value of unknowns that make the equation true. When dealing with linear equations, the goal is to isolate the variable you are solving for, usually by using basic arithmetic operations like addition, subtraction, multiplication, or division.
When you solve for a variable, you're essentially "breaking down" the equation. You simplify it step by step until the variable stands alone on one side of the equation. This process is structured and logical, much like peeling the layers of an onion until you reach the core.
Let's consider our example: the equation was initially \(4x + 3y = 12\). If given \(y = -4\), we substitute first, and through arithmetic operations, we eventually find \(x = 6\). This final number is the "solution" for that particular case.
To ensure accuracy:
When you solve for a variable, you're essentially "breaking down" the equation. You simplify it step by step until the variable stands alone on one side of the equation. This process is structured and logical, much like peeling the layers of an onion until you reach the core.
Let's consider our example: the equation was initially \(4x + 3y = 12\). If given \(y = -4\), we substitute first, and through arithmetic operations, we eventually find \(x = 6\). This final number is the "solution" for that particular case.
To ensure accuracy:
- Always perform the inverse operation to both sides of the equation
- Check your work by plugging the solution back into the original equation
Algebraic Substitution
Substitution is a method used in algebra to make calculations easier, especially when you have an equation with two variables. When you substitute, you're essentially replacing one variable with a given value or expression.
In the problem we solved, the technique involves directly replacing \(y\) with \(-4\) in the equation \(4x + 3y = 12\). This allows us to focus solely on finding the value of \(x\), simplifying the problem to a one-variable equation.
Substitution is incredibly valuable because:
In the problem we solved, the technique involves directly replacing \(y\) with \(-4\) in the equation \(4x + 3y = 12\). This allows us to focus solely on finding the value of \(x\), simplifying the problem to a one-variable equation.
Substitution is incredibly valuable because:
- It reduces the complexity of the original equation
- Makes the equation easier to work with by focusing on just one unknown at a time
- Is a frequently used strategy in solving systems of equations
Other exercises in this chapter
Problem 64
Multiply. $$\frac{1}{4} \cdot 4$$
View solution Problem 64
Translate each sentence below into an equation, then solve the equation. The difference of 9 and \(6 x\) is 21
View solution Problem 64
Find the value of each of the following expressions when \(x=3 .\) You may substitute 3 for \(x\) in each expression the way it is written, or you may simplify
View solution Problem 64
Write the mathematical expressions that are equivalent to each of the following English phrases. The difference of 4 and \(x\)
View solution