Problem 64
Question
Stella runs a business out of her home making quilts. Each month she has fixed costs of \(200. In addition, for each quilt she makes, she incurs an additional cost of \)1.75. If her total costs for the month were $280.50, how many quilts did she make?
Step-by-Step Solution
Verified Answer
Stella made 46 quilts.
1Step 1: Analyze the Problem
We need to find out how many quilts Stella made given her total cost and the cost structure. This involves isolating the variable that represents the number of quilts.
2Step 2: Establish the Equation
Let the number of quilts be \( q \). The total cost equation given the fixed monthly cost and the variable cost per quilt is \( 200 + 1.75q = 280.50 \).
3Step 3: Solve for the Variable
Subtract the fixed cost from each side of the equation: \( 1.75q = 280.50 - 200 \), which simplifies to \( 1.75q = 80.50 \).
4Step 4: Isolate the Variable
Divide both sides by 1.75 to solve for \( q \): \( q = \frac{80.50}{1.75} \).
5Step 5: Calculate the Solution
Perform the division: \( q = 46 \). Therefore, Stella made 46 quilts.
Key Concepts
Equation SolvingVariable IsolationWord Problems
Equation Solving
Solving an equation is like unraveling a math puzzle. You're trying to find the value of a variable that makes a mathematical statement true. In the problem about Stella and her quilts, we started by establishing an equation based on her costs and the number of quilts she made. The equation we formed was:
- Fixed monthly cost: \(200
- Variable cost per quilt: \)1.75
- Total cost: $280.50
Variable Isolation
Variable isolation is a vital step in solving equations. It means getting the variable by itself on one side of the equation. Think of it as finding the missing piece in a jigsaw puzzle. In our example, the variable \(q\) is the number of quilts. To isolate \(q\), follow these steps:
- First, subtract the fixed costs from both sides: \(1.75q = 280.50 - 200\).
- This simplifies to \(1.75q = 80.50\).
- Next, divide both sides by the coefficient of \(q\), which is 1.75: \(q = \frac{80.50}{1.75}\).
Word Problems
Word problems involve applying mathematical concepts to real-life situations. They can initially seem tricky, but they're just equations in disguise. The key is to translate the text into a mathematical equation. Let's break down the process using Stella's quilt-making business.
- Identify the costs: Fixed and variable.
- Write out the expression: Total cost = Fixed cost + (Cost per quilt \(\times\) Number of quilts).
- Form the equation based on the situation described.
Other exercises in this chapter
Problem 63
Convert the given decimal to a fraction. Reduce your answer to lowest terms. 0.06
View solution Problem 64
Compute the exact value of the given expression. \(-6 \sqrt{576}-8 \sqrt{121}\)
View solution Problem 64
Simplify the given expression. \(\frac{13}{8}+8.4\)
View solution Problem 64
Divide the decimals. \(\frac{-6.072}{0.66}\)
View solution