Problem 64
Question
Rocket A passes Earth at a speed of \(0.75 c\). At the same time, rocket B passes Earth moving \(0.95 c\) relative to Earth in the same direction. How fast is B moving relative to A when it passes \(A ?\)
Step-by-Step Solution
Verified Answer
Answer: The relative speed of Rocket B with respect to Rocket A is approximately 0.9926c.
1Step 1: 1. Understand the relativistic velocity addition formula
The relativistic velocity addition formula is given by:
$$
V = \frac{u+v}{1+\frac{uv}{c^2}}
$$
where \(V\) is the relative speed of the two objects, \(u\) is one object's speed relative to a reference frame (in this case, Earth), \(v\) is the other object's speed relative to the same reference frame, and \(c\) is the speed of light.
2Step 2: 2. Substitute the given values into the formula
In our problem, the speed of Rocket A relative to Earth is \(u = 0.75c\), and the speed of Rocket B relative to Earth is \(v = 0.95c\). We'll now substitute these values into the relativistic velocity addition formula:
$$
V = \frac{(0.75c) + (0.95c)}{1 + \frac{(0.75c)(0.95c)}{c^2}}
$$
3Step 3: 3. Simplify the expression
We can simplify the expression by factoring out \(c\) in the numerator and canceling out with the \(c^2\) in the denominator:
$$
V = \frac{c(0.75 + 0.95)}{1 + \frac{0.75 \cdot 0.95}{1}}
$$
4Step 4: 4. Calculate the relative speed
Now, we can compute the relative speed by solving for V:
$$
V = \frac{c(1.7)}{1 + 0.7125}
$$
$$
V = \frac{1.7c}{1.7125}
$$
$$
V \approx 0.9926c
$$
So, Rocket B is moving at a speed of approximately \(0.9926c\) relative to Rocket A when it passes Rocket A.
Key Concepts
Special RelativitySpeed of LightRelative Motion
Special Relativity
Special relativity is a fundamental theory proposed by Albert Einstein in 1905 to address inconsistencies between classical mechanics and electromagnetic theory. The theory fundamentally altered our understanding of time and space, introducing the concept that the laws of physics are the same for all non-accelerating observers, and that the speed of light in vacuum is constant regardless of the observer's motion or the motion of the source.
- Special relativity introduces the idea that time and space are interconnected in a four-dimensional spacetime continuum.
- This concept leads to phenomena such as time dilation and length contraction, where time could seem to pass slower, and lengths can appear contracted depending on the relative speed of the observer.
Speed of Light
The speed of light, denoted as \(c\), is one of the key constants in physics, valued at approximately \(299,792,458\) meters per second. It is not only a measure of how fast light moves through a vacuum, but it also sets a fundamental speed limit for the universe. No object with mass can achieve or exceed this speed, because as an object's speed approaches the speed of light, its mass effectively becomes infinite, and it would require infinite energy to move faster.
- The speed of light is vital in calculations in special relativity, particularly when applying the relativistic velocity addition formula.
- In the problem of rockets, the speeds are given as fractions of \(c\), such as \(0.75c\) and \(0.95c\).
Relative Motion
Relative motion refers to the calculation of one object's motion from the viewpoint of another object, often a crucial concept in scenarios involving high-speed travel, like spacecrafts and rockets. In the context of special relativity, relative motion takes on a complex nature because velocities that are significant fractions of the speed of light need to be combined using the relativistic velocity addition formula, instead of simply being added together.
- The formula \(V = \frac{u+v}{1+\frac{uv}{c^2}}\) accounts for the effects of special relativity when determining the relative velocity.
- The expression resolves the issue of combining speeds in a way that aligns with the constancy of the speed of light.
Other exercises in this chapter
Problem 59
Calculate the Schwarzschild radius of a black hole with the mass of a) the Sun. b) a proton. How does this result compare with the size scale \(10^{-15} \mathrm
View solution Problem 63
Using relativistic expressions, compare the momentum of two electrons, one moving at \(2.00 \cdot 10^{8} \mathrm{~m} / \mathrm{s}\) and the other moving at \(2.
View solution Problem 67
The explosive yield of the atomic bomb dropped on Hiroshima near the end of World War II was approximately 15.0 kilotons of TNT. One kiloton is about \(4.18 \cd
View solution Problem 68
At what speed will the length of a meter stick look \(90.0 \mathrm{~cm} ?\)
View solution