Problem 64
Question
Multiply. Then simplify if possible. Assume that all variables represent positive real numbers. $$ (3 \sqrt{x}+2)(\sqrt{3 x}-2) $$
Step-by-Step Solution
Verified Answer
The product is \(3x\sqrt{3} - 6\sqrt{x} + 2\sqrt{3x} - 4\).
1Step 1: Distribute First Terms
Begin by distributing the first term of the first binomial, which is \( 3 \sqrt{x} \), over the second binomial \( (\sqrt{3x} - 2) \). Multiply \( 3 \sqrt{x} \times \sqrt{3x} \) and \( 3 \sqrt{x} \times -2 \):\[ 3 \sqrt{x} \times \sqrt{3x} = 3 \sqrt{x} \cdot \sqrt{3x} = 3 \sqrt{3x^2} = 3 \times x \sqrt{3} = 3x\sqrt{3} \]\[ 3 \sqrt{x} \times -2 = -6 \sqrt{x} \]
2Step 2: Distribute Second Terms
Distribute the second term of the first binomial, which is \( 2 \), over the second binomial \( (\sqrt{3x} - 2) \). Multiply \( 2 \times \sqrt{3x} \) and \( 2 \times -2 \):\[ 2 \times \sqrt{3x} = 2 \sqrt{3x} \]\[ 2 \times -2 = -4 \]
3Step 3: Combine Like Terms
Combine all the results from the distribution:\[ 3x \sqrt{3} - 6 \sqrt{x} + 2 \sqrt{3x} - 4 \]Note that there are no like terms to combine in this expression, so this is the simplified polynomial.
Key Concepts
Polynomial SimplificationDistribution in AlgebraRadical Expressions
Polynomial Simplification
Polynomial simplification is the process of reducing a polynomial expression to its simplest form. This involves several steps like eliminating like terms, reducing fractions, and ensuring there are no unnecessary terms. In our exercise \((3 \sqrt{x}+2)(\sqrt{3 x}-2)\), we deal with a product of two binomials. After expansion by distribution, we get the expression:
- 3x \sqrt{3} - 6 \sqrt{x} + 2 \sqrt{3x} - 4
- There are no like terms left to combine.
- The terms are arranged systematically.
Distribution in Algebra
Distribution in algebra plays a crucial role in multiplying expressions, particularly when dealing with binomials. In the original exercise \((3 \sqrt{x}+2)(\sqrt{3 x}-2)\), we use distribution to expand the expression. Here’s a step-by-step breakdown of the distribution process:
- Multiply the first term of the first binomial by each term of the second binomial.
- Repeat the above step with the second term of the first binomial.
- The results are:\(3 \sqrt{x} \cdot \sqrt{3x} = 3x \sqrt{3}\) and \(3 \sqrt{x} \cdot -2 = -6 \sqrt{x}\).
- Then, \(2 \cdot \sqrt{3x} = 2 \sqrt{3x}\) and \(2 \cdot -2 = -4\).
Radical Expressions
Radical expressions involve roots, such as square roots, of variables or numbers. They can be tricky to handle if not approached correctly. The original problem includes terms like \(\sqrt{x}\) and \(\sqrt{3x}\). Here’s how to manage and understand them:
- When multiplying radicals with the same index, combine them under a single radical. For instance, \(\sqrt{x} \cdot \sqrt{3x} = \sqrt{3x^2}\), which simplifies to \(x\sqrt{3}\).
- Radicals can be distributed over addition and subtraction, aiding in simplification.
- Always simplify the radicand (the expression under the radical) as much as possible.
Other exercises in this chapter
Problem 64
Use rational exponents to simplify each radical. Assume that all variables represent positive real numbers. $$ \sqrt[4]{36} $$
View solution Problem 64
Use the quotient rule to divide. Then simplify if possible. Assume that all variables represent positive real numbers. \(\frac{\sqrt[3]{10}}{\sqrt[3]{2}}\)
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Divide. Write your answers in the form \(a+b i\) $$ \frac{6+8 i}{3 i} $$
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Rationalize each numerator. Assume that all variables represent positive real numbers. \(\frac{2-\sqrt{11}}{6}\)
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