Problem 64
Question
Let \(f(x)=3 x-2\) and \(g(x)=x^{2}+x .\) Find each of the following. $$ (f \circ g)(x) $$
Step-by-Step Solution
Verified Answer
The expression \((f \circ g)(x)\) is \(3x^2 + 3x - 2\).
1Step 1: Understand the Composition
The function notation \((f \circ g)(x)\) means we need to find the value of the function \(f\) when the output of the function \(g\) is input into \(f\). This involves substituting \(g(x)\) into \(f(x)\).
2Step 2: Substitute g(x) into f(x)
We need to replace every \(x\) in \(f(x) = 3x - 2\) with \(g(x)\), which is \(x^2 + x\). Therefore, substitute \(g(x)\) into \(f\), resulting in \(f(g(x)) = 3(x^2 + x) - 2\).
3Step 3: Simplify the Expression
Distribute the 3 through the expression \(3(x^2 + x) - 2\). This results in \(3x^2 + 3x - 2\).
4Step 4: Write Final Expression
The expression \((f \circ g)(x)\) is now simplified to \(3x^2 + 3x - 2\).
Key Concepts
Understanding Polynomial FunctionsDecoding Function NotationExploring Algebraic Expressions and Their Manipulations
Understanding Polynomial Functions
Polynomials are fundamental expressions in algebra. They are composed of variables, coefficients, and exponents, using basic operations such as addition, subtraction, and multiplication. A polynomial function is typically written as:
In the exercise, the function \(g(x) = x^2 + x\) is a polynomial function with a quadratic term \(x^2\). It's crucial to understand that you can perform operations like adding, subtracting, or substituting these polynomials just like numerical expressions.
- Constant terms (e.g., 5)
- Linear terms (e.g., \(3x\))
- Quadratic terms (e.g., \(x^2\))
- Cubic terms (e.g., \(x^3\)), and so on.
In the exercise, the function \(g(x) = x^2 + x\) is a polynomial function with a quadratic term \(x^2\). It's crucial to understand that you can perform operations like adding, subtracting, or substituting these polynomials just like numerical expressions.
Decoding Function Notation
Function notation is a compact way to express the input-output relationship in mathematics. When you see a symbol like \(f(x)\), it indicates a function named \(f\) with \(x\) as the variable input. Such notations allow mathematicians to write complex equations simply, focusing on relationships instead of mere calculations.
An important aspect is understanding composition, denoted by \((f \circ g)(x)\). This means you apply function \(g\) first and then take its result as an input to function \(f\). Essentially, you're layering functions, much like a nesting doll. This composition creates a new function that conveys the entire process in one expression.
For example, in the given exercise, \(f(g(x))\) means substituting \(g(x)\) into \(f(x)\). It's a seamless process that consolidates two functions into a single operational statement.
An important aspect is understanding composition, denoted by \((f \circ g)(x)\). This means you apply function \(g\) first and then take its result as an input to function \(f\). Essentially, you're layering functions, much like a nesting doll. This composition creates a new function that conveys the entire process in one expression.
For example, in the given exercise, \(f(g(x))\) means substituting \(g(x)\) into \(f(x)\). It's a seamless process that consolidates two functions into a single operational statement.
Exploring Algebraic Expressions and Their Manipulations
Algebraic expressions form the backbone of algebra, a branch of mathematics that uses symbols to represent numbers and operations. A simple algebraic expression might look like \(3x^2 + 3x - 2\), made up of terms consisting of constants and variables.
One major skill in manipulating algebraic expressions is substitution. This involves replacing a variable with another expression or value. In function composition, this skill is vital as seen when substituting \(g(x)\) for \(x\) in \(f(x)\). It transforms the original function into a new expression with ease.
When simplifying expressions, understanding distributive properties helps distribute terms correctly across the parentheses, efficiently breaking down complex expressions into simpler parts.
For instance, in the exercise, distributing the \(3\) across \(x^2 + x\) results in \(3x^2 + 3x\), which is then adjusted by subtracting \(2\), leading to the final combined expression: \(3x^2 + 3x - 2\). Knowing these manipulations solidifies the foundation for solving a vast array of algebraic and functional problems.
One major skill in manipulating algebraic expressions is substitution. This involves replacing a variable with another expression or value. In function composition, this skill is vital as seen when substituting \(g(x)\) for \(x\) in \(f(x)\). It transforms the original function into a new expression with ease.
When simplifying expressions, understanding distributive properties helps distribute terms correctly across the parentheses, efficiently breaking down complex expressions into simpler parts.
For instance, in the exercise, distributing the \(3\) across \(x^2 + x\) results in \(3x^2 + 3x\), which is then adjusted by subtracting \(2\), leading to the final combined expression: \(3x^2 + 3x - 2\). Knowing these manipulations solidifies the foundation for solving a vast array of algebraic and functional problems.
Other exercises in this chapter
Problem 64
Solve each equation. Express all answers to four decimal places. See Example 5. $$ \ln x=0.926 $$
View solution Problem 64
Solve each equation. Give the exact solution and, when appropriate, an approximation to four decimal places. $$ \ln x=5 $$
View solution Problem 64
Explain why the graph of \(f(x)=3^{x}\) gets closer and closer to the \(x\) -axis as the values of \(x\) decrease. Does the graph ever cross the \(x\) -axis? Ex
View solution Problem 64
Solve for \(x\). See Example 3 . $$ \log _{12} x=0 $$
View solution