Problem 64
Question
Is \(-\frac{5}{6}\) a solution of the equation \(\frac{1}{4}+x=-\frac{7}{12} ?\)
Step-by-Step Solution
Verified Answer
Yes, \(-\frac{5}{6}\) is a solution of the equation \(\frac{1}{4}+x=-\frac{7}{12}\)
1Step 1: Substitute
Substitute \(-\frac{5}{6}\) for \(x\) in the equation, \(\frac{1}{4}+x=-\frac{7}{12}\). So, the equation turns into \(\frac{1}{4}-\frac{5}{6}\)
2Step 2: Simplify
Simplify the left-hand side of the equation: Both \(\frac{1}{4}\) and \(-\frac{5}{6}\) should be converted into similar fractions so that they can be added together. To create like terms, convert \(\frac{1}{4}\) to \(\frac{3}{12}\) and \(-\frac{5}{6}\) to \(-\frac{10}{12}\). Then, \(\frac{3}{12}-\frac{10}{12}=-\frac{7}{12}\)
3Step 3: Compare
Compare the simplified left-hand side \(-\frac{7}{12}\) with the right-hand side \(-\frac{7}{12}\). As both are the same, we can conclude that \(-\frac{5}{6}\) is indeed a solution to the equation.
Key Concepts
Understanding Fractions in EquationsSolution VerificationSimplification Process
Understanding Fractions in Equations
When dealing with fractions in algebraic equations, it's essential to know how to manipulate them. Fractions represent parts of a whole and appear frequently in algebra. In this problem, the equation involves two fractions: \(\frac{1}{4}\) and \(-\frac{5}{6}\). To solve or verify the solution of an equation containing fractions, we often must create common denominators.
This allows us to add or subtract them easily. Common denominators transform fractions into like terms, making it simple to carry out operations.
You can find a common denominator by identifying the least common multiple (LCM) of the denominators.
This allows us to add or subtract them easily. Common denominators transform fractions into like terms, making it simple to carry out operations.
You can find a common denominator by identifying the least common multiple (LCM) of the denominators.
- In our problem, the LCM of 4 and 6 is 12.
- Convert \(\frac{1}{4}\) to \(\frac{3}{12}\) and \(-\frac{5}{6}\) to \(-\frac{10}{12}\).
Solution Verification
Verifying a solution involves checking if the proposed solution satisfies the original equation. After substituting the value of \(x = -\frac{5}{6}\) into the equation, we simplify the expression.
We combined the fractions to calculate the left-hand side: \(\frac{3}{12} - \frac{10}{12} = -\frac{7}{12}\).
Next, compare this with the right-hand side of the equation, which is also \(-\frac{7}{12}\).
We combined the fractions to calculate the left-hand side: \(\frac{3}{12} - \frac{10}{12} = -\frac{7}{12}\).
Next, compare this with the right-hand side of the equation, which is also \(-\frac{7}{12}\).
- If both sides match, your solution is correct.
- If they don't, the value substituted is not a solution.
Simplification Process
Simplification is the process of making an equation easier to understand or solve.
It often involves reducing fractions and performing basic arithmetic operations.
In our exercise, we simplified the left side by converting fractions to have a common denominator.
It often involves reducing fractions and performing basic arithmetic operations.
In our exercise, we simplified the left side by converting fractions to have a common denominator.
- Reduce fractions: Convert denominators to be the same to perform operations easily.
- Perform operations: Calculate the addition or subtraction of fractions once denominators are alike.
Other exercises in this chapter
Problem 64
Write the expression in words. $$-a-b$$
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Is \(-6\) a solution of the equation \(48=-8 y ?\)
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Insert one set of parentheses in the expression \(6-12 \div 2 \cdot 3-5^{2}\) to make the equation true. $$6-12 \div 2 \cdot 3-5^{2}=-21$$
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Identify the property that justifies the statement. $$-7+(3+2)=(-7+3)+2$$
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