Problem 64
Question
In Problems , find the coordinates of all of the points of the graph of \(y=f(x)\) that have horizontal tangents. $$ f(x)=2-x^{2} $$
Step-by-Step Solution
Verified Answer
The point with a horizontal tangent is (0, 2).
1Step 1: Understand the Problem
We need to find the points on the curve of the function \( f(x) = 2 - x^2 \) where the tangent to the curve is horizontal. This means the slope of the tangent is zero.
2Step 2: Find the Derivative
To find where the tangent is horizontal, we first need to calculate the derivative of the function, \( f'(x) \), which represents the slope of the tangent line at any point \( x \). For \( f(x) = 2 - x^2 \), use the power rule to differentiate.\[ f'(x) = \frac{d}{dx}(2-x^2) = 0 - 2x = -2x \]
3Step 3: Set the Derivative Equal to Zero
Since a horizontal tangent has a slope of zero, we set the derivative \( f'(x) \) equal to zero and solve for \( x \).\[ -2x = 0 \]
4Step 4: Solve for x
Solve the equation \( -2x = 0 \) to find the x-coordinate where the tangent is horizontal.\[ x = 0 \]
5Step 5: Find the y-coordinate
To find the y-coordinate, substitute \( x = 0 \) back into the original function \( f(x) \).\[ f(0) = 2 - (0)^2 = 2 \]
6Step 6: State the Coordinates
The point on the graph where the tangent is horizontal is \((0, 2)\).
Key Concepts
DerivativesTangent linesPower ruleSlope of a tangent
Derivatives
In calculus, a derivative represents a fundamental concept which allows us to determine the rate at which a function changes. Finding the derivative, denoted as \( f'(x) \), of a given function \( f(x) \) helps identify how the value of \( f \) changes as \( x \) changes. This is crucial in understanding the behavior of functions.
Derivatives are important because they give us the slope of the tangent line to the function at any given point. This slope is essentially the instantaneous rate of change — showing how fast or slow something occurs.
Derivatives are important because they give us the slope of the tangent line to the function at any given point. This slope is essentially the instantaneous rate of change — showing how fast or slow something occurs.
- To find the derivative of a simple polynomial function, like \( f(x) = 2 - x^2 \), we use different rules of differentiation including the power rule.
- Differentiation transforms the original function into a new function, providing insights on the original function's rate of change.
Tangent lines
A tangent line is a straight line that just "touches" a curve at a particular point, without crossing over. It represents the instantaneous direction of the curve at that specific point.
In the context of calculus, tangent lines are crucial for understanding the slope or rate of change of the curve at a given point.
In the context of calculus, tangent lines are crucial for understanding the slope or rate of change of the curve at a given point.
- For the function \( f(x) = 2 - x^2 \), the tangent line at any point \( x \) is calculated using the derivative \( f'(x) \).
- The tangent line at the point \((x_0, f(x_0))\) can be given by the equation \( y = f'(x_0) \cdot (x - x_0) + f(x_0) \).
Power rule
The power rule is a basic technique used to find the derivative of functions of the form \( x^n \), where \( n \) is any real number. It provides a quick and effective way to compute derivatives, especially useful for polynomial functions.
The power rule states that if \( f(x) = x^n \), then the derivative \( f'(x) = n \cdot x^{n-1} \).
The power rule states that if \( f(x) = x^n \), then the derivative \( f'(x) = n \cdot x^{n-1} \).
- In our exercise, the function \( f(x) = 2 - x^2 \) incorporates the power rule for \( x^2 \), resulting in the simple derivative \( f'(x) = -2x \).
- Using the power rule helps in swiftly solving derivative-related problems, simplifying the differentiation process.
Slope of a tangent
The slope of a tangent line is a key concept in calculus, representing how steep a line is at the point where it touches the curve. It is obtained from the derivative of the function at that specific point.
For the function \( f(x) = 2 - x^2 \), finding \( f'(x) \) gives us the slope of the tangent line at any \( x \).
For the function \( f(x) = 2 - x^2 \), finding \( f'(x) \) gives us the slope of the tangent line at any \( x \).
- A horizontal tangent line has a slope of zero, indicating no increase or decrease at the point where the tangent touches the curve.
- In the exercise, we found \( f'(x) = -2x \), and setting this equal to zero helps locate where the slope is zero—hence identifying the horizontal tangent.
Other exercises in this chapter
Problem 64
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Graph each function and, on the basis of the graph, guess where the function is not differentiable. (Assume the largest possible domain.) $$ y=\left|2 x^{2}-1\r
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Assume that the side length \(x\) and the volume \(V=x^{3}\) of a cube are differentiable functions of \(t .\) Express \(d V / d t\) in terms of \(d x / d t\)
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